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mars1129 [50]
3 years ago
13

Find the interquartile range (IQR) of the data set of 0,0,0,1,2,2,4,5,7,8,10​

Mathematics
1 answer:
myrzilka [38]3 years ago
7 0

Answer:7

Step-by-step explanation:

0,0,0,1,2,2,4,5,7,8,10

Median=2

Lower half=0,0,0,1,2

Upper half=4,5,7,8,10

Median in lower half=0

Median in upper half=7

Interquartile range=median in upper half - median in lower half

Interquartile range=7 - 0

Interquartile range=7

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alexandr1967 [171]

Step-by-step explanation:

Our coordinates are (6, 0) and (0, -3).

We can use the formula (y₂-y₁)/(x₂-x₁) to find the slope-intercept form (y=mx+b)

Now, we plug the coordinates into the formula and solve.

(0-(-3))/(6-0)

=3/6

=\frac{1}{2}

So, the slope is \frac{1}{2}.

Now, we have to find the y-intercept, which is the point where the line on the graph intersects with the y-axis.

We can find the y-intercept (which is represented by b) by plugging the information we already know into the formula.

We can use either pair of coordinates for the formula, so I'll use (6, 0).

y=mx+b

0=\frac{1}{2}(6)+b

Now, we can solve.

0=3+b

Subtract 3 from both sides.

-3=b

The y-intercept is -3.

Answer:

y=\frac{1}{2}x-3

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2 years ago
I need help with this question can you help me
Debora [2.8K]

Answer:

28.26ft

Step-by-step explanation:

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6 0
3 years ago
Is the following function even, odd or neither? f(x)=x^3 +4x
erica [24]

Answer:

D, neither

Step-by-step explanation:

to determine whether a function is even, odd or neither, we need to know what it means

an even function is symmetric with respect to the y-axis

an odd function is symmetric with respect to the origin

to solve an equation to see if its even or odd, we would need to substitute <em>x</em> in the equation for <em>-x</em>.

in an even function when we substitute f(-x), it should be equal to to f(x)

in an odd function when we substitute f(-x), it should be equal to -f(x)

so lets test the function given to see if its even

f(x) = x³ + 4x

f(-x) = (-x)³ + 4(-x)

f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to the orignal function, we see that f(-x) = x³ - 4x is not even as we did not get the same output as the original function

now we should test to see if its odd. we have already seen what f(-x) is, now lets try -f(x) and compare it to f(-x) and f(x)

-f(x) = -(x³ + 4x) -->

-f(x) = -x³ - 4x ≠ f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to f(x) and f(-x), we see that it not odd as we did not get the same output

so the answer is D, neither even nor odd

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belka [17]
48 feet
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3 years ago
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