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TiliK225 [7]
3 years ago
13

yen calculates the product 5/8 x 24/25. before he multiplies, he simplifies all the factors. what does the problem look like aft

er he simplifies the factors?
Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0
You know * comes before / if its  (5/8) you will start from divide.
(0.62 x 0.96)  or 5/8   24/25  look!!
you gonna make like this 8 x 25 and 25 x 8 
after that you gonna do 25 x 5  and 8 x 24 then add and then done
 
PolarNik [594]3 years ago
5 0
\frac{1}{1} *  \frac{3}{5}


Hope this helps!
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Answer:

The x-intercept is where the line crosses through the x-axis while y-intercept is when it crosses the y-axis,

1)x-intercept:4

y-intercept:2

2)x-intercept:-1

y-intercept:4

3)x-intercept:-3

y-intercept:3

hope this helps :)

6 0
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find the center of the circle that can be circumscribed about triangle EFG, E(6,4) F(6,2) and G(10,2)
Sindrei [870]
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Fencing How much fencing is required to enclose a circular garden whose radius is 28 ​m? Use 3.14 for . About nothing m of fenci
Andru [333]

Answer:

175.84 m

Step-by-step explanation:

Given that:

A circular garden which has a radius of 28 m.

\pi = 3.14

To find:

The fencing required to enclose the circular garden ?

Solution:

Here, we are given a circle and its radius.

We are required to find the perimeter of the circle in order to find the fencing required to enclose the circular garden..

Formula for finding the perimeter of a circle is:

Perimeter = 2\pi r

where r is the radius of the circle.

Using the given values in the formula:

Perimeter = 2\times 3.14 \times 28 = <em>175.84 m</em>

Therefore, 175.84 m of fencing is required.

8 0
3 years ago
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ahrayia [7]
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5 0
2 years ago
Read 2 more answers
Which point lies on a circle with a radius of 5 units and center at P(6,1)?
ryzh [129]

Answer:

Option B. R(2,4)

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

(x-6)^{2}+(y-1)^{2}=5^{2}

(x-6)^{2}+(y-1)^{2}=25

step 2

Verify each case

case A) Q(1, 11)

substitute the value of x=1, y=11 in the equation of the circle and then compare the results

(1-6)^{2}+(11-1)^{2}=25

25+100=25 ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) R(2,4)

substitute the value of x=2, y=4 in the equation of the circle and then compare the results

(2-6)^{2}+(4-1)^{2}=25

16+9=25 ------> is true

therefore

the ordered pair R lie on the circle

case C) S(4,-4)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(4-6)^{2}+(-4-1)^{2}=25

4+25=25 ------> is not true

therefore

the ordered pair S not lie on the circle

case D) T(9,-2)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(9-6)^{2}+(-2-1)^{2}=25

9+9=25 ------> is not true

therefore

the ordered pair T not lie on the circle

7 0
3 years ago
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