Finding the Bearing<span> of a </span>Ship<span>
Example : A </span>ship<span> leaves the port of Miami with a </span>bearing<span> of S80◦E and a </span>speed<span> of. 15 knots. After 1 hour, the </span>ship<span> turns 90◦ toward the south.</span>
Answer:
C. (5x^3-7)(2x^2+1)
Step-by-step explanation:
Given expression is,
10x^5+5x^3-14x^2-7
=10x^5-14x^2 + 5x^3 - 7 (By the commutative property)
=2x^2(5x^3-7)+5x^3-7 (Taking 2x^3 common from first two terms )
=(5x^3-7)(2x^2+1) (Taking 5x^3-7 common from both terms)
\implies 10x^5+5x^3-14x^2-7=(5x^3-7)(2x^2+1)
Hence, Option C is correct
The answer is -4k^2 - 21k - 20! so sorry if I’m wrong but it’s the answer I got :>
The answer would be A.132 because when you add the corner length to 90 it equals 132
Answer:
2
Step-by-step explanation:
well if you get all of the fractions into percentage form they will be 20%for green 8% for blue so in turn it would mean 8% of 15 is 2
