They gave you an eqution with variables and then they gave you numbers that all you have to do is put in
k(h-j)+h
5(5-4)+5
5(1)+5
5+5
10
The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;

We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
For more information refer to the link.
brainly.com/question/15070282
Answer:
13.8
Step-by-step explanation:
Recall the trigonometric ratios
Sine = Opposite over Hypotenuse (SOH)
Cosine = Adjacent over Hypotenuse (CAH)
Tangent = Opposite over Adjacent (TOA)
Now lets look back at the question
We are given an angle and its adjacent side length (11) and we need to find the hypotenuse
The hypotenuse and adjacent sides corresponds with the trig function cosine so we will use cosine to solve for x
( remember that cosine = adjacent over hypotenuse )

step 1 multiply each side by x

now we have 
step 2 divide each side by cos(37)

we're left with x = 13.77439
Our last step would be to round to the nearest tenth
We would get that the answer is 13.8