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Anna007 [38]
3 years ago
12

If you are given distance and period of time, what can you calculate?

Physics
2 answers:
ira [324]3 years ago
8 0

D. speeds

because you gotta go fast jk if take mph miles per hour that's a distance and a time there for you would be able to calculate speed

mash [69]3 years ago
3 0

speed

this is correct i took the test

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A small water droplet in a mist of air is approximated as being a sphere of diameter 1.25 mil. Calculate the terminal velocity a
shtirl [24]

The terminal velocity as it falls through still air is 4.65154 in/s.

The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m

                                                                            = 3.175 × 10^-5 m

Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa

 So the formula for drag force is:

                Fd = 6πηrv

  where,  v is the velocity.

Now to attain terminal velocity acceleration must be zero.

            →  W = Fd

                ρVg = 6πrηv

                ρ × 4/3 πr³×g = 6πrηv

                           v = 2/9 × ρgr³/ η

                           v =  2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6

                           v = 0.1181  m/s

                           v = 4.65154 in/s

Learn more about terminal velocity here:

     brainly.com/question/20409472

              #SPJ4

                   

8 0
2 years ago
The starships of the Solar Federation are marked with the symbol of the Federation, a circle, whereas starships of the Denebian
Llana [10]

Complete question

The complete question is shown on the first uploaded image  

Answer:

The velocity is  v = c* \sqrt{1 -  \frac{1}{n^2} }

Explanation:

From the question we are told that

           a = nb

The length of the minor axis  of  the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the  Empire's symbol, (an ellipse)

Now this length seen by the observer can be mathematically represented as

        h = t \sqrt{1 - \frac{v^2}{c^2} }

Here t  is the actual length of the major axis of of the  Empire's symbol, (an ellipse)

So t = a = nb

and  b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the  Empire's symbol, (an ellipse)

 i.e    h = b

So

    b  =  nb  [\sqrt{1 - \frac{v^2}{c^2} } ]  

     [\frac{1}{n} ]^2 =  1 -  \frac{v^2}{c^2}

      v^2 =c^2 [1- \frac{1}{n^2} ]

       v^2 =c^2 [\frac{n^2 -1}{n^2} ]

        v = c* \sqrt{1 -  \frac{1}{n^2} }

     

     

6 0
3 years ago
A water-balloon launcher with mass 5 kg fires a 1 kg balloon with a velocity of
Mashcka [7]

1.6 m/s west is the answer

3 0
3 years ago
HELP ME PLEASE I NEED IT NOW
tia_tia [17]

Answer:

the angle of incident is 40°

Explanation:

NQ is the normal to the mirror, therefore

angle NQA =90°

PQA = 50°

incident angle = NQA - PQA

90°- 50° = 40°

note that the angle of reflection is equal to the angle of incident

8 0
3 years ago
If you don’t know please move on if you know please help:)
frozen [14]

Answer:

When a magnet causes a paper clip to move, it's an example of Potential energy being changed in to Kinetic energy

A child running is an example of Kinetic energy

A motionless iron object in the magnetic field of a magnet may be said to have Potential energy

6 0
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