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2 years ago

Im

Physics

1 answer:

kvasek [131]2 years ago

7 0

<h3>A wave is a ( DISTURBANCE) that carries (ENERGY) from one place to another.</h3>

Hope this helps.

Good luck ✅.

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A crude approximation is that the Earth travels in a circular orbit about the Sun at constant speed, at a distance of 150,000,00

Savatey [412]

Answer:

The answer is "Option B".

Explanation:

$r=15\times 10^{7}\ km\ = 15\times 10^{10}\ m\\\\w=\frac{2\pi}{1\ year}\\\\=\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec}\\\\a=w^2r\\\\=(\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec})^2 \times 15 \times 10^{10}\ \frac{m}{s^2}\\\\$

$=5.940 \times 10^{-3} \ \frac{m}{s^2}\\\\=6 \times 10^{-3} \ \frac{m}{s^2}\\\\=0.006\ \frac{m}{s^2}\\\\$

7 0

3 years ago

Help please!!! 100 points

NeX [460]

1. Acceleration
2. If you are going 12 meters per second and you want to know how many seconds it takes yo get to 105 meters, you need yo find how long it takes to go horizontally then vertically. 12 seconds.
3. B

8 0

3 years ago

Read 2 more answers

A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is

ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0$

Solving the above equation we get

$t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89$

So, the time the package was in the air is 1.97 seconds

3 0

3 years ago

How does heating a gas rigid container change its pressure

gavmur [86]

The particles are heating up so they are starting to move faster and closer together which causes them to change the pressure of the container

6 0

3 years ago

A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 24.3 m/s . A 1.0-kg stone is thrown

defon

Answer:

-969.06

-286.74

698.7

-115.6, 12.9

-139.9, 12.9

Explanation:

Given that

Speed v, wrt y = -24.3 m/s

Speed v, wrt x = 12.9 m/s

time t, = 11.8 s

Using the formula

H(t) = ut - 1/2gt², where u = v wrt y

H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²

H(t) = -286.74 - 682.28

H(t) = -969.06 m

H = ut, where u = v wrt y

H = -24.3 * 11.8

H = -286.74 m

H(1) = -969.06 - -286.74 = -682 m

Horizontal displacement, x = vt. Where v = v wrt x

x = 12.9 * 11.8

x = 152.22 m

d = √(H1² + x²)

d = √682² + 152²

d = 465124 + 23104

d = √488228

d = 698.7 m

Vertical component =

-gt - 0 =

-9.8 * 11.8 = -115.6

Horizontal component =

v wrt x - 0

12.9 - 0 = 12.9

Vertical component =

-gt - v wrt y =

-9.8 * 11.8 - 24.3 = -139.9

Horizontal component =

v wrt x - 0 =

12.9 - 0 = 0

8 0

3 years ago