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Lena [83]
3 years ago
14

Which one of the following is NOT an evidence of the Big Bang Theory? A. most objects in space are moving away from one another

B. cosmic microwave background radiation C. the light from objects in space is “blue shifted” D. most of the universe is made from light elements, hydrogen and helium
Physics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
Hello there!

The correct answer to your question is c.

This is because one of the main claims to the Big Bang Theory is that "the universe is constantly expanding outwards."

When various objects, say galaxies, recede from us, their light's wavelength is elongated. This, in turn, results as the galaxy's light to look red.

When these objects are moving <em>closer</em> to us, it shortens the wavelength, creating a blue light. In terms of the Big Bang Theory, this should not happen, because everything is moving <u>out</u>.

I hope this helps!
Brady
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Choose true or false for each statement regarding a parallel plate capacitor.. The voltage of a disconnected charged capacitor i
OlgaM077 [116]

Answer:

Explanation:

The voltage of a disconnected charged capacitor increases when the plate area is decreased.

When plate area decreases , capacitance C decreases , but charge Q remains constant .

Q = C V where C is capacitance and V is voltage .

when C decreases , V increases for keeping Q constant .

So the statement is true.

The electric field is dependent on the charge density on the plates.

This statement is true .

The voltage of a connected charged capacitor remains the same when the plate area is decreased .

For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .

So the statement is true .

3 0
3 years ago
The note created by a flute will increase the speed of sound increases. When a marching band goes outside on a cold day, what wo
alexgriva [62]

A).

It would decrease because the speed of sound and temperature are proportional.

4 0
3 years ago
Read 2 more answers
If blue light hits a red filter, what kind of light comes through the filter?
kotegsom [21]
It can be either C or B

Reasons it can be C: Red and Blue together(if I'm correct in art) is the combined color of two of the 3 primary colors to get a purple/violet color and if said filter is see through or just too dense for the light to even penetrate the said filter(in theory) but all in all purple is the answer with the two primary colors blue and red.

But also, it depends on what kind of filter it is, if the filter is like a screen filter then it will just come out in blue with the slightly different colors of again purple but in a darker tone then the actual eye can see.

Or it can be just C again cause the filter can be a film but that's a bit too far and to complex for right now so I believe it is B
8 0
3 years ago
g Estimate the number of photons emitted by the Sun in a second. The power output from the Sun is 4 × 1026 W and assume that th
vagabundo [1.1K]

Answer:

The value is N  =  1.107 *10^{45 }  \ photons    

Explanation:

From the question we are told that

   The  power output from the sun is  P_o =  4 * 10^{26} \  W

   The average wavelength of each photon is  \lambda  = 550 \  nm  =  550 *10^{-9} \  m

Generally the energy of each photon emitted is mathematically represented as

        E_c =  \frac{h * c  }{ \lambda }

Here  h is the Plank's constant with value  h  =  6.62607015 * 10^{-34} J \cdot s

          c is the speed of light with value  c =  3.0 *10^{8} \  m/s

So

       E_c =  \frac{6.62607015 * 10^{-34}  * 3.0 *10^{8}  }{ 550 *10^{-9} }          

=>   E_c =  3.614 *10^{-19} \  J          

Generally the  number of photons emitted by the Sun in a second is mathematically represented as

         N  =  \frac{P }{E_c}

=>      N  =  \frac{4 * 10^{26} }{3.614 *10^{-19}}

=>      N  =  1.107 *10^{45 }  \ photons    

5 0
2 years ago
You have a source of energy containing 21 gj of energy at 600k how much this energy can be converted to work when rejecting heat
sweet [91]

Answer:

Available energy = 35 x 10⁶ J

Explanation:

Given:

Amount of energy (Q) = 21 gj = 21 x 10⁹ J

Temperature T1 = 600 k

Temperature T0 = 27 + 273 = 300k

Find:

Available energy

Computation:

Available energy = Q[1/T0 - 1/T1]

Available energy = 21 x 10⁹ J[1/300 - 1/600]

Available energy = 35 x 10⁶ J

4 0
2 years ago
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