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Georgia [21]
3 years ago
15

What is the initial position

Physics
1 answer:
labwork [276]3 years ago
6 0

Answer:

Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.

hope it is helpful...

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Now, look at a general function f(x), as shown in (Figure 4) .
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We can't look at Figure 4. We don't know where a and b are. We can't see the blue shaded area. We don't know what our method above was. We can't see the green skinny rectangle.
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What is manipulating the arrangement of DNA that makes up a gene is called
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Manipulating the arrangement of DNA that makes up a gene is called genetic engineering.
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A constant force is exerted on a cart that is initially at rest on a frictionless air track. The force acts for a short time int
Inessa05 [86]

Let <em>F</em> be the magnitude of the force applied to the cart, <em>m</em> the mass of the cart, and <em>a</em> the acceleration it undergoes. After time <em>t</em>, the cart accelerates from rest <em>v</em>₀ = 0 to a final velocity <em>v</em>. By Newton's second law, the first push applies an acceleration of

<em>F</em> = <em>m a</em>   →   <em>a</em> = <em>F </em>/ <em>m</em>

so that the cart's final speed is

<em>v</em> = <em>v</em>₀ + <em>a</em> <em>t</em>

<em>v</em> = (<em>F</em> / <em>m</em>) <em>t</em>

<em />

If we force is halved, so is the accleration:

<em>a</em> = <em>F</em> / <em>m</em>   →   <em>a</em>/2 = <em>F</em> / (2<em>m</em>)

So, in order to get the cart up to the same speed <em>v</em> as before, you need to double the time interval <em>t</em> to 2<em>t</em>, since that would give

(<em>F</em> / (2<em>m</em>)) (2<em>t</em>) = (<em>F</em> / <em>m</em>) <em>t</em> = <em>v</em>

3 0
3 years ago
A bullet with kinetic energy of 400J strikes a wooden block where a 8.00x10N resistive force stops the bullet what is the penetr
tia_tia [17]

The "penetration of the bullet" is 5 m

<u>Explanation</u>:

A "bullet" with "kinetic energy" of = 400J

A resistive force stops the bullet  = 8.00 x 10 N

Work = change in energy  

Work = ∆ Kinetic Energy   (equation 1)

Work = F\times d   (equation 2)

From equations 1 and 2 we have,

F\times d = ∆ Kinetic Energy

Where ,

Kinetic Energy = 400 J

F = 8.00 x 10 N

(8.00 x 10 N) d = 400 J

(80 N) d = 400 J

d=\frac{400}{80}

d = 5 m

The penetration of the bullet is 5 m

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How many electrons do alkali metals have in their outer shell?
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The outer shell can hold 1 electron
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Read 2 more answers
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