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Georgia [21]
3 years ago
15

What is the initial position

Physics
1 answer:
labwork [276]3 years ago
6 0

Answer:

Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.

hope it is helpful...

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How do some producers use sunlight to make "food"? What other resources do they require?
Talja [164]
<span>Leaves of plants absorb light from the sun.Leaves of plants also absorb the air that people breathe out, called carbon dioxide.Leaves of plants also absorb water. ...Leave</span><span>How Do Primary Producers Make Their Own Food? - Tech Alive</span><span>techalive.mtu.edu/meec/module10/Howarenutrientscycledinaschoolyardecology.htm</span>s of plants use light from the sun to turn the air people breathe out and water into glucose and oxygen. GOT IT FROM 
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3 years ago
An object is raised 2.5m off the ground. That object has a mass of 10kg, how many joules of potential energy is stored in the ob
klio [65]

Answer:

245.25 J

Explanation:

Potential Energy = m g h

                         = 10 * 9.81 * 2.5 = 245.25 J

4 0
2 years ago
Every 6 seconds a pendulum completes one cycle. 
Basile [38]

The period is the time it takes any repeating process
to complete one cycle.  You just told us what it is for the
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that's

                 1 / (6 sec) = (1/6) per second = 1/6 Hertz .

4 0
3 years ago
Read 2 more answers
A car is sitting motionless on top of a bridge. The bridge pushes up on the car with a force of 782 Newtons.
Evgesh-ka [11]

Answer: The car would move to the right with 150 n of force. the 150 n of force from friction and air resistance slows the car from moving to the right with 300 n of force.

Explanation:

3 0
2 years ago
A proton and an electron are both accelerated to the same final speed. If λp s the de Broglie wavelength of the proton and e is
meriva

Answer:

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

\lambda =\frac{h}{m\times v}

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.  

So, the de broglie wavelength of proton is given by

\lambda _{p}=\frac{h}{m_{p}\times v} .... (1)

The de broglie wavelength of electron is given by

\lambda _{e}=\frac{h}{m_{e}\times v} .... (2)

Divide equation (2) by equation (1), we get

\frac{\lambda _{e}}{\lambda _{p}}=\frac{m_{p}}{m_{e}}

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

5 0
3 years ago
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