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kompoz [17]
2 years ago
6

Explain why materials such as plastic foam, feathers, and fur are poor conductors of heat.

Physics
1 answer:
vampirchik [111]2 years ago
8 0
They are poor conductors because they keep the heat trapped in one spot, while other materials like metal let the heat go through itself.
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An object has a forward force of 100N and a reverse force of 25N. What is the resultant force?
iragen [17]

<u>Given</u><u>:</u>

  • An object has a forward force = 100N

  • An object has a reverse force = 25N

<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>

What is the resultant force?

<u>Solution</u><u>:</u>

Resultant Force = Forward force + Reserve force

= 100 N + ( - 25 N )

= 75 N

4 0
3 years ago
Read 2 more answers
Gas
Brut [27]
A: what is it called when a solid jumps straight to a gas?
B: what is it called when a liquid becomes a gas?
C: what is it called when a solid changes into a liquid?

Im sure you can at least figure out the last one! (hint: this happens when ice becomes water)
3 0
3 years ago
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Which of the following wire gage sizes is the thickest? <br> A. 8<br> B. 10<br> C. 14<br> D. 0
maks197457 [2]
A because it's the smaller the thicker you just can't have 0 gage
5 0
3 years ago
A fox fleeing from a hunter encounters a 0.700 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.
iris [78.8K]

Answer:0.61 m

Explanation:

Given

Initial velocity (u)=7.40 m/s

launch angle \theta =45^{\circ}

height of fence=0.7 m

Trajectory of Projectile is given by

y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }

For x=2.1 m  

y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}

y=2.1-0.789

y=1.31 m

At x=2.1 m Y=1.31

therefore Fox clear fence by a margin =1.31-0.7=0.61 m

7 0
3 years ago
Consider the standing wave pattern below created by a string fixed at both ends. The string is under a tension of 0.98 N and has
Shalnov [3]

Answer:

11.07Hz

Explanation:

Check the attachment for diagram of the standing wave in question.

Formula for calculating the fundamental frequency Fo in strings  is V/2L where;

V is the velocity of the wave in string

L is the length of the string which is expressed as a function of its wavelength.

The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)

Therefore L = 1.5λ

If L = 3.0m

1.5λ = 3.0m

λ = 3/1.5

λ = 2m

Also;

V = √T/m where;

T is the tension = 0.98N

m is the mass per unit length = 2.0g = 0.002kg

V = √0.98/0.002

V = √490

V = 22.14m/s

Fo = V/2L (for string)

Fo = 22.14/2(3)

Fo = 22.14/6

Fo = 3.69Hz

Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo

Frequency of the wave = 3×3.69

Frequency of the wave = 11.07Hz

3 0
3 years ago
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