<u>Given</u><u>:</u>
- An object has a forward force = 100N
- An object has a reverse force = 25N
<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>
What is the resultant force?
<u>Solution</u><u>:</u>
Resultant Force = Forward force + Reserve force
= 100 N + ( - 25 N )
= 75 N
A: what is it called when a solid jumps straight to a gas?
B: what is it called when a liquid becomes a gas?
C: what is it called when a solid changes into a liquid?
Im sure you can at least figure out the last one! (hint: this happens when ice becomes water)
A because it's the smaller the thicker you just can't have 0 gage
Answer:0.61 m
Explanation:
Given
Initial velocity (u)=7.40 m/s
launch angle 
height of fence=0.7 m
Trajectory of Projectile is given by
For x=2.1 m
At x=2.1 m Y=1.31
therefore Fox clear fence by a margin =1.31-0.7=0.61 m
Answer:
11.07Hz
Explanation:
Check the attachment for diagram of the standing wave in question.
Formula for calculating the fundamental frequency Fo in strings is V/2L where;
V is the velocity of the wave in string
L is the length of the string which is expressed as a function of its wavelength.
The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)
Therefore L = 1.5λ
If L = 3.0m
1.5λ = 3.0m
λ = 3/1.5
λ = 2m
Also;
V = √T/m where;
T is the tension = 0.98N
m is the mass per unit length = 2.0g = 0.002kg
V = √0.98/0.002
V = √490
V = 22.14m/s
Fo = V/2L (for string)
Fo = 22.14/2(3)
Fo = 22.14/6
Fo = 3.69Hz
Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo
Frequency of the wave = 3×3.69
Frequency of the wave = 11.07Hz