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umka21 [38]
3 years ago
15

Gas

Physics
2 answers:
Ipatiy [6.2K]3 years ago
7 0

Answer:

A-Sublimation

B-Vaporization

C-Melting

Explanation:

Correct on EDG 2021

Brut [27]3 years ago
3 0
A: what is it called when a solid jumps straight to a gas?
B: what is it called when a liquid becomes a gas?
C: what is it called when a solid changes into a liquid?

Im sure you can at least figure out the last one! (hint: this happens when ice becomes water)
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Your teacher gives you a piece of cardboard with two pinholes on it, saying that they are separated by 205 μm ± 3%. In order to
wlad13 [49]

Answer:

m,lkj,mkn,njn

Explanation:because she is telling you to do a project

7 0
3 years ago
A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?
devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120   Divide by 120

150/120 = I

5/4  = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by  √2

3 0
3 years ago
Read 2 more answers
If 'P' represents white color flowers and 'p' represents purple color flowers, and you cross a PP plant with a pp plant, what wi
satela [25.4K]
The genotype for all offspring will be Pp making the flower color white.
4 0
2 years ago
A sled starts from rest,
Marrrta [24]

Answer:

25.6 m/s

Explanation:

Draw a free body diagram of the sled.  There are two forces acting on the sled:

Normal force pushing perpendicular to the hill

Weight force pulling straight down

Take sum of the forces parallel to the hill:

∑F = ma

mg sin θ = ma

a = g sin θ

a = (9.8 m/s²) (sin 38.0°)

a = 6.03 m/s²

Given:

v₀ = 0 m/s

a = 6.03 m/s²

t = 4.24 s

Find: v

v = at + v₀

v = (6.03 m/s²) (4.24 s) + (0 m/s)

v = 25.6 m/s

5 0
3 years ago
What is the impulse of a 2 kg object that starts at 10 m/s and comes to a stop over 0.4 seconds?
gizmo_the_mogwai [7]

Answer: Impulse = 20 Ns

Explanation:

Impulse is the product of force and time

Also impulse = momentum

Where momentum is the product of mass and velocity.

Given that

M = 2kg

V = 10 m/s

Impulse = MV = 2 × 10 = 20 Ns

8 0
3 years ago
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