Answer:
A Shunt is a passive element, usually resistive, that is used to bypass current around another element, like a meter, that is not able to handle the full current flow. ... A Multiplier is an active element that amplifies a voltage or current to enable a less sensitive device or circuit to make use of it.
The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
<h3>What is concave mirror?</h3>
A concave mirror has a reflective surface that is curved inward and away from the light source.
Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.
<h3>
Object distance of the concave mirror</h3>
Apply mirrors formula as shown below;
1/f = 1/v + 1/u
where;
- f is the focal length of the mirror
- v is the object distance
- u is the image distance
when image height = object height, magnification = 1
u/v = 1
v = u
Substitute the given parameters and solve for the distance of the object from the mirror's vertex
1/f = 1/v + 1/v
1/f = 2/v
v = 2f
v = 2(19.5 cm)
v = 39 cm
Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
Learn more about concave mirror here: brainly.com/question/27841226
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Answer:
<em>1.Magnetic Force - Used in cranes to separate metal junk from junkyards.</em>
<em>2.Frictional Force- Helps us to walk.</em>
Answer:
Follows are the solution to this question:
Explanation:
Please find the correct question in the attachment file.
Let:
Calculating the value of 
![\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]](https://tex.z-dn.net/?f=%5Cto%20%5Cleft%20%7C%20%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7BK%7D%5C%5CR_i%26R_j%26R_k%5C%5CS_i%26S_j%26S_k%5Cend%7Barray%7D%5Cright%20%7C%20%3D%20%5Chat%7Bi%7D%5BR_j%20S_k-S_jR_k%5D-%5Chat%7Bj%7D%5BR_i%20S_k-S_iR_k%5D%2B%5Chat%7Bk%7D%5BR_i%20S_j-S_iR_j%5D)
Calculating the value of 
![\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])](https://tex.z-dn.net/?f=%5Cto%20%28R_i%5Chat%7Bi%7D%2BR_j%5Chat%7Bj%7D%2BR_k%5Chat%7Bk%7D%29%20%5Ccdot%20%28%20%5Chat%7Bi%7D%5BR_j%20S_k-S_jR_k%5D-%5Chat%7Bj%7D%5BR_i%20S_k-S_iR_k%5D%2B%5Chat%7Bk%7D%5BR_i%20S_j-S_iR_j%5D%29)
by solving this value it is equal to 0.
