A soap bar because the material of a carpet or sandpaper is more rough than a soapbar and thus has a higher coefficient of friction.
Answer:
option d) -9 J
Explanation:
Given:
Mass, m = 3.0 kg
time, t = 6.0 seconds
Velocity of mass, v = 2.0 m/s
height, h = 2 m
Now, using the concept of work-Energy theorem
we have
Net work done = change in kinetic energy
or
Work done by gravity + work done by the friction = Final kinetic energy - Initial kinetic energy
mgh +
= 
on substituting the values in the above equation, we get
3 × 9.8 × 2 +
= 
or
58.8 +
= 6
or
= -52.8 J
here negative sign depicts that the work is done against the motion of the mass
also,
Power = (Work done)/time
or
Power = -52.8/6 = -8.8 W ≈ 9 J
Hence, option d) -9 J is correct
Answer:
Approximately
(assuming that
.)
Explanation:
Let
denote the force that this spring exerts on the object. Let
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant
of this spring would ensure that
.
Note that the mass of the object attached to this spring is
. Thus, the weight of this object would be
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus,
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that
is negative since this displacement points downwards.)
Rearrange Hooke's Law to find
in terms of
and
:
.
The answer for this question is acceleration
200N
Explanation:
600N-400N = 200N