Question

A fox fleeing from a hunter encounters a 0.700 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.40 m/s at an angle of 45.0º, beginning the jump 2.10 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.

Answer 1

Answer:0.61 m

Explanation:

Given

Initial velocity (u)=7.40 m/s

launch angle $\theta =45^{\circ}$

height of fence=0.7 m

Trajectory of Projectile is given by

$y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }$

For x=2.1 m  

$y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}$

$y=2.1-0.789$

$y=1.31 m$

At x=2.1 m Y=1.31

therefore Fox clear fence by a margin =1.31-0.7=0.61 m