<h2>
Answer</h2>
The answer to this question is 
<h2>
Explanation</h2>
As we know that accelartion is the rate of change of velocity. So, it can be write as

where
is the final velocity
is the initial velocity
t is the time
a is the accelartion
as we konw

t = ?
From rest So,
= 0
Putting values




So, the right answe is 
As per the question there are three physical quantities named as position,distance and displacement.
Before coming into a conclusion first we have to understand a vector and a scalar.
A scalar quantity is a quantity which has only magnitude for it's complete specifications.
A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.
Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.
Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.
Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.
Hence position and displacement are vectors
1) 1025km per 13.5hr = 1025km/13.5hr = 75.9 km/hr
2) 400km per 30min = 400km/30min = 13.3 km/min
13.3km/min X (60min per hr) = 13.3km/min(60min/hr) = 800km/hr
3) 45km/hr in 40min = 45km/hr X 40min X (1hr/60min) = 30km.
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4) (30m/s - 10m/s) per 10s = 20m/s/10s = 2ms/s = 2m/s/s = 2m/s^2 </span>
Answer:
Explanation:
When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.
When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other .So both the shells lose their charges .The positive half shell also loses all its charges
When we separate the half shells , there will be no deflection in the electroscope because both the shell have already lost their charges and they have become neutral bodies . So they will not be able to produce any deflection in the electroscope.
Answer:
I think no.2 the answer
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