Answer:
![V_2=3.3m/s](https://tex.z-dn.net/?f=V_2%3D3.3m%2Fs)
Explanation:
From the question we are told that:
Distance ![d_1=1.4m](https://tex.z-dn.net/?f=d_1%3D1.4m)
Tangential speed ![V=2.2m/s](https://tex.z-dn.net/?f=V%3D2.2m%2Fs)
Distance 2 ![d_2=2.1m](https://tex.z-dn.net/?f=d_2%3D2.1m)
Generally the equation for Angular velocity is mathematically given by
![w=\frac{v}{r}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7Bv%7D%7Br%7D)
Therefore
![\frac{v_1}{r_1}=\frac{v_2}{r_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_1%7D%7Br_1%7D%3D%5Cfrac%7Bv_2%7D%7Br_2%7D)
![V_2=\frac{2.2*2.1}{1.4}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B2.2%2A2.1%7D%7B1.4%7D)
![V_2=3.3m/s](https://tex.z-dn.net/?f=V_2%3D3.3m%2Fs)
The centrifugal force working against the car would be the entire car's weight, so the centripetal force that is supplied to the car must be the car's tires traction, aka the friction of the car's tires and the surface.
Answer:
F=Gm1m2 / r2
Explanation:
F = force
G = gravitational constant
m_1 = mass of object 1
m_2 = mass of object 2
r = distance between centres of the masses
Net force can be defined as the sum of force acting on an object in all the directions
.i.e Net force= F acting on a body at upward direction+ F at downward direction+ F at leftward direction+ F at rightward direction.
e.g if a body is at rest the sum of forces acting on body in all direction is zero
but if a body is moving its mean body is facing an unbalanced net force.