Answer:
Cellular respiration that proceeds in the absence of oxygen is anaerobic respiration. Cellular respiration that proceeds in the presence of oxygen is aerobic respiration.
Answer:
The chlorophyll inside the plants cells give the plants its pretty, green colour.
Answer:
The correct answer is D
Explanation:
The cell membrane is essentially composed of the following:
- phospholipids
- cholesterol
- proteins
The phospholipid consists of a <em>hydrophilic </em>phosphate 'head' and the tail is the <em>hydrophobic</em> fatty acid chain.When cellular membranes form,phospholipids collect into two layers in light of these hydrophilic and hydrophobic properties. The phosphate heads in each layer face the fluid or watery condition on either side, and the tails conceal away from the water between the layers of heads, since they are hydrophobic.
There are 3 main factors that greatly influence the fluidity of the plasma membrane:
- temperature
- cholesterol
- saturated and unsaturated fatty acids
The compound eyes of insects <span>detect color and form images. The correct option among all the options that are given in the question is the first option or option "A". The other options are close but they are incorrect. I hope that this is the answer that has actually come to your help.</span>
<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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