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pychu [463]
3 years ago
8

A rectangular cake has a length of 22 1/2 inches and a width of 10 inches. How many whole, square pieces of cake with side lengt

hs of 2 1/2 inches can be cut from the cake?
Mathematics
1 answer:
faltersainse [42]3 years ago
5 0
Well, we need to find the area of the cake.  22.5 times 10 is 225.  That is the area then we need to find the area of each piece of cake.  2.5 times 2.5 is 6.26.
so divide the area of the cake by the area of each piece to find how many pieces can be cut.
225/6.25=36  36 pieces of cake can be cut from the cake
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3 years ago
Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2
Arturiano [62]
2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
\boxed{5x=0} \Leftarrow \hbox{the mistake, it should be 5x=20} \\
x=0 \\ \\
2(0)+y=5 \\
y=5

If 2x+y=5, then y=5-2x, so he substituted 5-2x correctly.
x+4x=5x, so he combined like terms correctly.
If 5x-10=10, then 5x=10+10 -> 5x=20, so he subtracted 10 from the right side instead of adding 10 to the right side.

The answer is C.

Here's the correct solution:
2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
5x=10+10 \\
5x=20 \\
x=\frac{20}{5} \\
x=4 \\ \\
y=5-2x \\
y=5 - 2 \times 4 \\
y=5-8 \\
y=-3 \\ \\
(x,y)=(4,-3)
5 0
3 years ago
How to do? Can anyone help me please? I will appreciate that a lot!
Nitella [24]
Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°

Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°

So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°

Final answers: ∠CDO = 120° and ∠ABD = 90°
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Point (, ) is dilated from the origin by scale factor = . What are the coordinates of point ′?
Igoryamba

Answer:idk how to do this im in 7th grade

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