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3 years ago

How i can prove the proofs?

Mathematics

1 answer:

Marianna [84]3 years ago

3 0

You can prove the proofs by showing your work to prove the proofs.

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Examples of rational numbers

diamong [38]

Examples of rational numbers :
1, 1/2, 3/4 , 5 , 6, 15/8 etc

Rational numbers are numbers which can be written as fraction as also that the numerator and denominator are whole examples.
Example 5 can be written as fraction in the form of 5/1.

7 0

4 years ago

A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with

irinina [24]

This is a mixture problem.

Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.

mass1 * karat1 + mass2*karat = total mass * total carat

Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18

Total mass = 200g.
Total karat = 14.

9*x + 18*(200 -x) = 14*200

9x + 18*200 - 18*x = 14*200

18*200 + 9x - 18x = 14*200

3600 - 9x = 2800

3600 - 2800 = 9x

800 = 9x

9x = 800

x = 800/9

x ≈ 88.89

Therefore 88.89 grams of 9 karat gold must be mixed.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

3 years ago

What procedure will find the sum a+b of two numbers where a and b represent any integer?

ElenaW [278]

Answer:As rational number includes natural number, whole number ,integers also.

⇒Natural number(1,2,3,4....) is a rational number also.

So, when A= Natural number , B=Any other natural number

Just add two natural number using simple law of addition.

⇒As Whole numbers(0,1,2,3,...) are Rational number also.

So If A=any whole number, B=Any other whole number

Add the whole number in any order using law of addition.

⇒Coming to integers (....-123,....-5,...-1,....12,....59,.....) By taking any two integers ,

1. Both of them are positive add using simple law of addition.

2. One of them is positive and other is negative , if larger one has positive sign before it just subtract smaller one from larger one and put positive sign before the result.and if larger one has negative sign before it ,subtract smaller one from larger one and put negative sign before the result.

⇒If both of them are negative , just add the two integers and apply negative sign before the result.

4. Rational number as fractions ,

A=m/n and B=p/q

A+B=m/n + p/q

find LCM of n and q.

If n and q are co-prime multiply n and q to get the LCM.For example if n=5, q=7, then LCM=5×7=35

If n and q are not co-prime find the factors of n and q .take out the common factors and then multiply the common factors with those factors which are not common.

For example, n=15, q=20

15=5×3

20=2×2×5

common factor=5

non common factor=2,2,3

LCM=5×2×2×3=60

Suppose LCM(n,q)= K

⇒p/q+m/n

So ,

which is the way to find LCM of rational number when theyare fractions.

Step-by-step explanation:

4 0