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4 years ago

Can you please show me how to calculate the volume for each prism?

Mathematics

1 answer:

larisa [96]4 years ago

8 0

Answer:

1st: volume = long x wide x high = 7 x [sqrt(25^2-7^2)] x 4 = 7 x 24 x 4 = 672

2nd: volume = area of base(circle) x high = pi x 9^2 x 8 = ~ 2035.8

3rd = volume = area of base(triangle) x high = [sqrt(3)/4] x 14^2 x 20 = ~1697.4

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I need help plz!!?!???!?

Ksivusya [100]

Answer:

Solution → (3, -1)

Step-by-step explanation:

We ave to identify the graph representing the system of lines first.

y = $\frac{2}{3}x-3$

Y-intercept of the line = -3

y = -2x + 5

y-intercept of the line = 5

From the given graphs 3rd (extreme right) graph is representing the system of equations.

Solution of the system of equations will be the point of intersection of these lines.

Solution of the system → (3, -1)

8 0

3 years ago

PLEASE HELP FOR 30 POINTS....GEOMETRY/TRIG

Advocard [28]

Answer:

10/cot 62 degrees

Step-by-step explanation:

5 0

3 years ago

Find three consecutive integers whose sum is 48

mart [117]

Answer:

our numbers should be 15, 16, and 17.

Step-by-step explanation:

n + n+1 + n+2 = 48.

8 0

3 years ago

If the gradient of the tangent to

Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \sqrt{x}$

$\displaystyle y' = \frac{1}{6}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{2}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x}}$

Step 3: Solve

Find coordinates of A.

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}$
[Multiplication Property of Equality] Cross-multiply: $\displaystyle \sqrt{x} = 3$
[Equality Property] Square both sides: $\displaystyle x = 9$