All categories

4 years ago

Can you please show me how to calculate the volume for each prism?

Mathematics

1 answer:

larisa [96]4 years ago

8 0

Answer:

1st: volume = long x wide x high = 7 x [sqrt(25^2-7^2)] x 4 = 7 x 24 x 4 = 672

2nd: volume = area of base(circle) x high = pi x 9^2 x 8 = ~ 2035.8

3rd = volume = area of base(triangle) x high = [sqrt(3)/4] x 14^2 x 20 = ~1697.4

You might be interested in

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago

A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?

ASHA 777 [7]

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = $5C3 m^{2} f^{3} + 5C2 m^{2} f^{3} + 5C1 m^{4} f + 5C0 m^{5} f^{0}$

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125

8 0

3 years ago

All designs should have a single feature that stands out over all the rest of the elements in the composition to which of the fo

Luden [163]

Dominance is the answer.

8 0

3 years ago

In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.

bezimeni [28]

Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2

3 0

3 years ago

Which of the following is a way that you would employ arithmetic in a real world situation?

otez555 [7]

Hey there! The answer is actually A. Choosing a grocery item based on a price per unit comparison.

I hope this helps you guys!

I have a screenshot attached as proof :)

4 0

3 years ago

Read 2 more answers