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3 years ago

write an expression containing x-terms and constants. The x-terms schould combine to 7x and the constants should sum to 13

Mathematics

1 answer:

S_A_V [24]3 years ago

6 0

<span>2x+12+6x+1-x You are adding up 2x and 6x and deduct 1x so you get 7x You add up 12 and 1 which gives 13</span>

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Solve for x using the quadratic formula x^2-6x +9=0

Rufina [12.5K]

Answer:

3 both ways x = 3

EXPLANATION:

plug in inputs and do a little simplifying we get

x = 6 ± √(36-36) all of that over 2

So we simplify and we get 6±sqrt(0) / 2

Then we get 6/2 = 3

x-0 = x+0

thats why there is only one answer

4 0

3 years ago

Read 2 more answers

Simplify the expression. (15 + 8)[23 – (10 + 7)]

wariber [46]

(23)(23-17)
(23)(6)
138

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4 years ago

Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more

Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1) (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2) (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3) (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c) + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0

3 years ago

There was a layer of snow on joes driveway when it began to snow again. As the snow fell, joe measure the depth, in centimeters

OLga [1]

The minutes will be ur x axis and the cm of snow will be ur y axis

(10,2),(30,3.6).....using 2 points and the slope formula : (y2 - y1) / (x2 - x1)

slope = (3.6 - 2) / (30 - 10) = 1.6 / 20 = 0.08 cm per minute <===

4 0

3 years ago

In 2010, the population of a town was 8500. The population decreased by 4.5% each year.

Soloha48 [4]

Answer:

This is a problem in exponential decay.

a) If a town's population decreases by 4.5% every year that also means that the town's population decreases by a factor of .955 each year. (1 - .045 = .955)

So, after 5 years, the town's population is:

8,500 * .955^5 which equals 6,752.

So, basically, after t years, the town's population equals

8,500 * .955^t where t is the number of years that have passed since the year 2010.

b) population = 8,500 * .955 ^ (number of years since 2010)

7,000 / 8,500 = .955 ^ (number of years since 2010)

0.8235294118 = .955 ^ (number of years since 2010)

To solve for (number of years since 2010) we take logs of both sides

log (0.8235294118 ) = number of years since 2010 * log(.955)

-0.0843208857 = number of years since 2010 * -0.0199966284

-0.0843208857 / -0.0199966284 = number of years since 2010

4.2167551422 = number of years since 2010

So, population = 7,000 when the year is 2014.2167551422

Or about 2.6 months into 2014

(YES, it's just that "easy") LOL

Step-by-step explanation:

6 0

3 years ago