What is the center of the circle that has a diameter whose endpoints are (9,7) and (-3,-5)

Mathematics

2 answers:

solong [7]4 years ago

6 0

subtract 9-(-3) = 12

12/2=6 subtract 6 from 9

9-6 = 3

subtract 7-(-5) = 12

12/2 = 6

subtract 7-6 = 1

so center of circle is (3,1)

Sergio039 [100]4 years ago

4 0

Midpoint formula gives (3,1)

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Can someone please answer this???? ASAP

timofeeve [1]

Answer:

A. $y=-\dfrac{8}{7}x-\dfrac{18}{7}$

Step-by-step explanation:

Let $y=mx+b$ be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is $\frac{7}{8}$ Hence,

$\dfrac{7}{8}\cdot m=-1\\ \\m=-\dfrac{8}{7}$

is the slope of needed line.

This line passes through the point (-4,2), so its coordinates satisfy the equation:

$2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}$

Therefore, the equation of the line is

$y=-\dfrac{8}{7}x-\dfrac{18}{7}$

7 0

3 years ago

What value for a makes this equation true? 6 • a = (6 • 30) + (6 • 2)

Alecsey [184]

Given:
6a = (6x30) + (6x2)

Find the value of a.

6a = (6x30) + (6x2)

As you notice, 6 is the common factor of each term
6a =6(30+2)
6a = 6(32)

To get the value of a, divide both sides by 6.
6a/6 = 6(32)/6

a = 32 CHOICE B.

6a = (6*30)+(6*2)
6(32) = 180 + 12
192 = 192

or you can solve the problem this way.

6a = (6*30)+(6*2)
6a = 180 + 12
6a = 192
6a/6 = 192/6
a = 32

4 0

3 years ago

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Sphinxa [80]

I hope this helps you