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4 years ago

12

What is the center of the circle that has a diameter whose endpoints are (9,7) and (-3,-5)

2 answers:

solong [7]4 years ago

6 0

subtract 9-(-3) = 12

12/2=6 subtract 6 from 9

9-6 = 3

subtract 7-(-5) = 12

12/2 = 6

subtract 7-6 = 1

so center of circle is (3,1)

Sergio039 [100]4 years ago

4 0

Midpoint formula gives (3,1)

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Help please is for Algebra

Sauron [17]

Answer:

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the third option is your answer

Step-by-step explanation:

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6 0

3 years ago

sketch the curve represented by the parametric equations (indicate the orientation of the curve), write the corresponding rectan

pychu [463]

Answer:

Reduced equaton is $5x-3y+\frac{28}{3}=0$ .

Step-by-step explanation:

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4 years ago

Read 2 more answers

(-5)^2-2x(-9)+6<br> Please show work and step by step.

Varvara68 [4.7K]

Answer:

<h2>49</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

==============================================

(-5)² - 2 × (-9) + 6 <em>first </em><em>E</em><em>xponents</em>

25 - 2 × (-9) + 6 <em>next </em><em>M</em><em>ultiplication</em>

25 + 18 + 6 <em>next </em><em>A</em><em>ddition</em>

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3 years ago