Given that x has a Poisson distribution with
1 answer:
The Poisson probability distribution function is
where
μ = mean number of successes
x = actual or expected number of successes
Given:
μ = 13
x = 5
Therefore the probability that x=5 is
P(x = 5) = (e⁻¹³*13⁵)/5!
= 0.8392/120
= 0.006994
= 0.0070 (to 4 dec. places)
Answer: 0.0070 (to 4 decimal places)
It is interesting to observe P(x) as x varies, as in the graph shown below.
where
μ = mean number of successes
x = actual or expected number of successes
Given:
μ = 13
x = 5
Therefore the probability that x=5 is
P(x = 5) = (e⁻¹³*13⁵)/5!
= 0.8392/120
= 0.006994
= 0.0070 (to 4 dec. places)
Answer: 0.0070 (to 4 decimal places)
It is interesting to observe P(x) as x varies, as in the graph shown below.
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<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>
Answer:
Step-by-step explanation:
<u>Powers of The Imaginary Unit</u>
The imaginary unit i is defined as
The first powers of i are
And so on the cycle repeats every four numbers. To find the value of we can find the remainder of 96/4=0. So
The given expression is
Factoring
Since
The required value is 0