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neonofarm [45]
3 years ago
5

What's 165% as a fraction and decimal

Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0
165% = 1.65 (decimal)

165% = 165/100 = 33/20 (fraction)
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Pls Help I’m stuckThere are 89 students in the Oakwood Middle School band. The number of boys in the band is 5 more than twice t
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Answer:

42

Step-by-step explanation:

5 more than 2 times the girls

89=5+2x

x=42

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Sandy is helping her uncle at this coffee shop. She observes that, when ordering coffee, 13 of customers select chocolate flavor
otez555 [7]
Answer: The probability that 3 or more of the next 5 customers will order chocolate is 30%.  3/10

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The fraction 30% is 3/10.
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2 years ago
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Please help I will give brainly and show your work also :)
hoa [83]
Use a calculator what?
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3 years ago
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The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a
r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation  of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

The degrees of freedom γ=n-1 =35-1=34

tₐ =  2.0322

99% confidence interval for average weights of all packages sold in small meat trays

(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

<u>(0.932 ,1.071)</u>

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2 years ago
Which equation has a graph that is a parabola with a vertex at (–2, 0)?
MaRussiya [10]

Answer:

The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.

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The possibilities are

y =  (x-2)^2

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Since the problem tells us the answer, we adopt the positive values

Answer:

y =  (x-2)^2

See attached picture

6 0
2 years ago
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