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3 years ago

What's 165% as a fraction and decimal

Mathematics

1 answer:

steposvetlana [31]3 years ago

6 0

165% = 1.65 (decimal)

165% = 165/100 = 33/20 (fraction)

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Line segmentAB has vertices A(−3, 4) and B(1, −2) . A dilation, centered at the origin, is applied to AB⎯⎯⎯⎯⎯ . The image has ve

zysi [14]

Answer:

The scale factor is

$\frac{1}{3}$

Step-by-step explanation:

Line segmentAB has vertices A(−3, 4) and B(1, −2) .

A dilation, centered at the origin, is applied to AB. The image has vertices

A'(-1,4/3) and B′(1/3, −2/3) .

We know the rule for dilation by scale factor of k, is

$(x,y)\to(kx,ky)$

This means that;

$A(-3,4)\to A'(-3k,4k)$

But we know, A' has coordinates (-1,4/3)

This means that

$- 3k = - 1$

$k = \frac{1}{3}$

We could also compare:

4k=4/3

Which gives

k=⅓

5 0

3 years ago

Read 2 more answers

Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

solong [7]

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

$\to \lim_{x\to 2} \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2} \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\$

$\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\$

$\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5$

5 0

3 years ago

Solve the given inequality and graph the solution on a number line. -x/3 + 5/2 < 2/2.

AleksAgata [21]

This is the working. the answer is x is less than half. the number line is beside it.

I hope it helped

8 0

3 years ago

An exterior angle of a regular convex polygon is 40°. What is the number of sides of the polygon?

seraphim [82]

Answer:

option B

Step-by-step explanation:

Sum of interior angles of a polygon with n sides:

$= (n - 2 )\times 180$

$Therefore, Each \ interior \ angle = (\frac{n - 2}{n} )\times 180$

$Sum \ of \ one \ of \ the \ interior \ angle \ with \ its \ exterior \ angle \ is \ 180^\circ$

$[ \ because \ straight \ line \ angle = 180^\circ \ ]$

That is ,

$Exterior \ angle + Interior \ angle = 180^\circ\\\\40^ \circ + (\frac{n-2}{n}) \times 180 = 180^\circ\\\\40 n + 180n - 360 = 180n\\\\40n = 180n - 180n + 360 \\\\40n = 360 \\\\n = 9$