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3 years ago

HELP ASAP Please!!!

Mathematics

2 answers:

Nookie1986 [14]3 years ago

5 0

True I think I could be wrong gotta get these points

lutik1710 [3]3 years ago

4 0

i pretty sure its false i could be wrong but i think its false

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In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo

Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

$P(B) = 0.6$

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

$P(A/B) = x$

P(A) is the probability that the participant dies:

$P(A) = P_{1} + P_{2} + P_{3}$

$P_{1}$ is the probability that a heavy smoker is selected and that he dies. So:

$P_{1} = 0.15*5x = 0.75x$

$P_{2}$ is the probability that a light smoker is selected and that he dies. So:

$P_{2} = 0.25*3x = 0.75x$

$P_{3}$ is the probability that a non-smoker is selected and that he dies. So:

$P_{3} = 0.60*x = 0.60x$

The probability that a participant dies is:

$P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x$

The probability of the participant being a non-smoker, given that he died, is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857$

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0

3 years ago

Translated 2 units right

melisa1 [442]

Answer:

yes

Step-by-step explanation:

3 0

3 years ago

Can anyone help me with this?

Serga [27]

I don't understand ur hand writing sorry

4 0

3 years ago

Complete the data set with one value so that the mean of the data is 7.

zlopas [31]

Add 2
Remove 8.........

6 0

3 years ago

Read 2 more answers

Two players, A and B, are playing an asymmetrical game. There are n points on the game board. Each turn player A targets a pair

nordsb [41]

The values of n that either player has a winning strategy is when the number of points are odd such as 3:-

<h3>How to depict the strategy?</h3>

The game is begun by A and then its chance of B to play the game alternatively, then all the possible moves are 1,2; 2,3; 1,3 in which all possible pairs are selected.

If the game end on an even number of moves then the game is won by A. For B to win, these points should be connected at the very end of the game.

Similarly, for even number of moves B wins the game when number of points is odd.

If the number of points is even the opposite of this happens that is, for even moves B wins and for odd number of moves A wins.

Learn more about strategy on:

brainly.com/question/24499246

#SPJ1

3 0

2 years ago