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tekilochka [14]
3 years ago
9

A small college needs two additional faculty members: a chemist and a statistician. There are five applicants for the chemistry

position and three applicants for the statistics position. In how many ways can the college fill these positions?
Mathematics
1 answer:
Mrac [35]3 years ago
3 0

Answer:

15 ways

Step-by-step explanation:

The events "choosing one out of 5 chemists" and "choosing one out of 3 statisticians" are independent, and, therefore, the number of ways that both positions can be filled is determined by the product of the number of ways that each event can occur:

n=3*5 =15\ ways

The college can fill these positions in 15 different ways.

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bonufazy [111]

Answer:

y=

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y=

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Step: Solvey=

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Step: Substitute

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x=−2 and y=−1

Step-by-step explanation:

Sorry if it is too confusing

5 0
2 years ago
Read 2 more answers
A geyser erupts every fourth day. Another geyser erupts every sixth day. Today both geysers erupted. In how many days will both
dimulka [17.4K]

Answer:

48

Step-by-step explanation:

Fourth day, sixth day, both geysers erupted

4 × 6 × 2 = 48

6 0
3 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
A printer toner company launches a new product. The number of pages that this new toner can print is normally distributed with a
Vitek1552 [10]

Answer:

Step-by-step explanation:

Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

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µ = mean

σ = standard deviation

From the information given,

µ = 2300 pages

σ = 150 pages

1)

the probability that this toner can print more than 2100 pages is expressed as

P(x > 2100) = 1 - P(x ≤ 2100)

For x = 2100,

z = (2100 - 2300)/150 = - 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.092

P(x > 2100) = 1 - 0.092 = 0.908

2) P(x < 2200)

z = (x - µ)/σ/√n

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z = (2200 - 2300)/150/√10

z = - 100/47.43 = - 2.12

Looking at the normal distribution table, the probability corresponding to the z score is 0.017

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3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is

- 1.88

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- 1.88 = (x - 2300)/150

150 × - 1.88 = x - 2300

- 288 = x - 2300

x = - 288 + 2300

x = 2018

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x < 2018 pages

4 0
3 years ago
Fill in the missing fraction or mixed number <br> __ + 1/4 = 5/8
gogolik [260]

3/8=answer

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<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8•4

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<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32=

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5 0
3 years ago
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