The equation given in the question has two unknown variables in the form of "x" and "y". The exact value of "x" and "y" cannot be determined as two equations are needed to get to the exact values of "x" and "y". This equation can definitely be used to show the way for determining the values of "x" in terms of "y"and the value of "y" in terms of "x". Now let us check the equation given.
2x - 5y = - 15
2x = 5y - 15
2x = 5(y - 3)
x = [5(y - 3)]/2
Similarly the way the value of y can be determined in terms of "x" can also be shown.
2x - 5y = - 15
-5y = - 2x - 15
-5y = -(2x + 15)
5y = 2x + 15
y = (2x +15)/5
= (2x/5) + (15/5)
= (2x/5) + 3
So the final value of x is [5(y -3)]/2 and the value of y is (2x/5) + 3.
Answer:
Individuals end to continue paying the premiums of the automobile insurance as a habit. However, serious thoughts and putting in element of strategizing helps to reduce the premium in most cases. At times, there is a sudden like on the part of the insurer even for a flawless driver.
A good look up and research of the insurance websites can be of real help in comparing whether a better deal is offered by the other insurance companies, or whether a certain change in the policy or small adjustments of the term would give benefit to the customer.
In case a speeding ticket is received, or an accident is mentioned in the driving history, it is maintained there in for a period of three to five years. Thus, the premium increases substantially. A change of insurer is advised in such situations, where a major search for an insurer, who does not pay that much importance to these details, is to be carried on.
Again, having a teenager driver in the family calls for a caution as the insurance premium increases drastically in such occasion. Having clean driving record of the parents, or kids commuting to far away schools without cars help in such situation.
use the Pythagoras theorem method
a squared plus b squared equals c square
Answer:
y = -5/4x -8
Step-by-step explanation:
There is a y-intercept of -8
There is a slope of -5/4
