I need some help really

Represent m < 3 on the number line. <br><br> (I’ll mark as brainliest if correct, thx)

FromTheMoon [43]

Answer:

____________________________

0 1 2 (3) 4 5 6 7 8 9 10

7 0

3 years ago

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16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o

Lynna [10]

Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

$E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)$

where $x_1,x_2,...,x_n$ are the values that the variable can take and $p(x_1),p(x_2),...,p(x_n)$ are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

$E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15$

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

$V(x)=E(x^2)-(E(x))^2$

Where $E(x^2)=x_1^2*p(x_1)+x_2^2*p(x_2)+...+x_n^2*p(n)$

So, the variance V(x) is equal to:

$E(x^2)=(0^2*0.92)+(1^2*0.03)+(2^2*0.03)+(3^2*0.02)=0.33\\V(x)=0.33-(0.15)^2\\V(x)=0.3075$

Finally, the standard deviation is calculated as:

$S(x)=\sqrt{V(x)} \\S(x)=\sqrt{0.3075} \\S(x)=0.5545$

8 0

3 years ago

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Casey has 48 peppers and 16 yellow peppers . If he wants to put the peppers into baskets so that each basket has the same number

liraira [26]

Answer:

3 red peppers and 1 yellow pepper in each basket.

Step-by-step explanation:

We have been given that Casey has 48 peppers and 16 yellow peppers. He wants to put the peppers into baskets so that each basket has the same number of red and yellow peppers. We are asked to find the number of red and yellow papers in each basket.

To solve our given problem, we need to find greatest common factor of 48 and 16.

Prime factorization of 48 is $2\times 2\times 2\times 2\times 3$ .