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Harrizon [31]
3 years ago
8

Both of these questions I️ got wrong. Please do not pay attention to my work because it is all wrong!

Mathematics
1 answer:
kaheart [24]3 years ago
8 0
11. The area of the circle is pi×r^2 so pi×6^2= 113.1cm^2 rounded to 1 d.p.
The area of the rectangle is 4×4=16cm^2
So to find out the area of the shaded region, do 113.1-16= 97.1cm^2

12. The area of a rectangle is l×w so 40×18=720cm^2
The area of the triangle is 1/2(l×w) so 1/2(9×12)=1/2(108)= 54cm^2
So to find out the area of the shaded region, do 720-54= 666cm^2
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Answer:

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Step-by-step explanation:

take the root of both sides then solve

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Please SHOW WORK, will mark brainlist if correct
riadik2000 [5.3K]

Answer:

\huge\boxed{\sf \frac{x+3}{x-3}}

Step-by-step explanation:

\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
SOLVE the EXPRESSION<br> Evaluate.<br> 2t2 - 18<br> +
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<h2>QUESTION:</h2>

Evaluate 2t2 - 18 + ( incomplete question )

<h2>SOLUTION:</h2>

▶️ 2t2 - 18

▶️ 2t × 2 - 18

▶️ 4t - 18

<h2>ANSWER:</h2>

4t - 18

4 0
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