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Vitek1552 [10]
3 years ago
10

Ariana earns 20% commission as a salesperson. She sold a ceramic vase that cost $78. How much commission did Ariana earn?​

Mathematics
1 answer:
frutty [35]3 years ago
8 0

Answer:

The answer is 15.6.

Step-by-step explanation:

20% of $78 = 15.6

Please mark as brainliest if this helped!

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The question is in the picture
GrogVix [38]

Ten-thousand   AFAFANDIUAHDIUAHIUDHAIDh (had to write 20 more "letters")


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3 years ago
A square purple rug has a orange square in the center. The side length of the orange square is x inches. The width of the purple
Liono4ka [1.6K]

Answer:

578 + 48 square inches

Step-by-step explanation:

The computation of the area of the purple band is as follows:

Area of the green square = side^2 = x^ square inches

And, the area of the orange square = side^2

The side would be = = 12 + 12 +x  = 24 + x

And, now the area would be = (x + 24)^2

Now the area of the orange band is

= Area of the orange square  area of the green square

= (x + 24)^2 - x^2

= x^2 + 24^2 + 48  - x^2

= 578 + 48 square inches

4 0
3 years ago
PLEASE ANSWER DONT IGNORE ): I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS
Lera25 [3.4K]

Answer:

Niether of them are correct

Step-by-step explanation:

If you actually put into your calculator 2^28, it equals 268,435,456. This is because you're not just squaring 28, you are multiplying 2 by 2-- 38 times. This will quickly add up, even if you start out with 2 it will create a very large number.

7 0
3 years ago
The expression 625(1−x) gives the discounted price of a television, where x is the percent of the discount written in decimal fo
bekas [8.4K]

the original price of the television

is your answer.

6 0
3 years ago
Read 2 more answers
Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
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