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MaRussiya [10]
3 years ago
15

The diameter was of four half circles are sides of a square with a side length of 7 cm.

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0
Idk how ill show work over this but i have something similar to this
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Two boards are 26 meters long altogether. One board is 8 meters long. How long is the other board?
Aleonysh [2.5K]
I think the answer is 18 because together, they are 26 meters and one is 8 so u have to subtract the total with 8 which is 26-8. the answer to that would be 18.
ANSWER: 18 meters
6 0
3 years ago
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How do you calculate the population mean
bazaltina [42]
Add up all the numbers then divide how many ever digits there are
7 0
3 years ago
Three coins are tossed in the air, one at a time. What is the probability that the third coin will be heads?
marishachu [46]

Answer:

1/2

Step-by-step explanation:

We only care about the third coin

we could get heads or tails on the third flip

P (third coin will be heads) = outcome heads / total

                                            =1/2

8 0
3 years ago
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Find the volume of the square pyramid showing. round to the nearest 10th if necessary
solong [7]
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).

Here the area of the base is (10 ft)^2 = 100 ft^2.

13 ft is the height of one of the triangular sides, but not the height of the pyramid.  To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft.  That "middle" is 5 units straight down from the upper vertex.  Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft).  What is the height of the pyramid?  
To find this, use the Pyth. Thm.:  (5 ft)^2 + y^2 = (13 ft)^2.  y = 12 ft.

Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
5 0
3 years ago
Tickets to a play cost $8.00 each.
jekas [21]

Answer:

Step-by-step explanation:

b + g = 8x

4 0
3 years ago
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