Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
18 juniors
10 seniors
6 female seniors
10-6 = 4 male seniors
12 junior males
18-12 = 6 junior female
6+6 = 12 female
4+12 = 16 male
A total of 28 students
The possibility of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S; So we have
P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
(Extra; but please give me brainliest
D, 1/12 pound. A way to think of this is that if there is 1/12 in 6 different bags, you get 6/12, which is equivalent to 1/2
The team has lost only 6 games (according to the comments). Let's say "x" is the amount of losses and "y" is the amount of wins.
For every loss, they have 3 wins, so in the end, this would be the equation:
or
Although the first one would be the easier and most understandable to read.
So:
y = 3(6)
would equal
18
Answer:
56
Step-by-step explanation:
1176 divided by 21 = 56
Answer:
There is not enough information to answer this question
Step-by-step explanation: