X^(2) + 10x=24 by completeing the square
1 answer:
(b/2)^2=(−5)^2
x^2−10x+(−5)^2=<span>24+<span>(−5)^<span>2
</span></span></span><span><span>x^2−10x+25</span>=49
</span><span><span>(x−5)^</span>2</span>=<span>49 (square root)
</span><span>(<span>x<span>−5</span></span>)</span>=<span>±<span>7
x-5=7 => x=12
x-5=-7 => x=-2</span></span>
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