The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}
<h3>Recursive function</h3>
Given the nth term of a recursive expression shown below
an =an-1 - 1.4
where
an-1 is the preceding term
a1 is the first term
an is the nth term
an-1 is
Given the following
a1 = 0
For the second term a2
a2 = 0 - 1.4
a2 = -1.4
For the third term a3
a3 = -1.4 - 1.4
a3 = -2.8
For the fourth term a4
a4 = -2.8 - 1.4
a4 = -4.2
For the fifth term a2
a5 = -4.2 - 1.4
a5 = -5.6
Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}
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15+(q/6)=-21
Subtract 15 from both sides
q/6= -36
Multiply both sides by 6.
q= -216
Answer:
The only non-zero fixed point is: x = 9/A.
The Step-by-step explanation:
A fixed point of a function is a points that is mapped to itself by the function; g(x) = x. Therefore, in order to find the fixed point of the given function we need to solve the following equation:
g(x) = x
x(10 - Ax) = x
10x - Ax² = x
10x - x -Ax² = 0
9x - Ax² = 0
Ax² - 9x = 0
The solutions of this second order equation are:
x = 0 and x = 9/A.
Since we are only asked for the non-zero fixed points, the solution is: 9/A.
Answer:
I think the answer is 13...
Step-by-step explanation:
f(3)=5*3-2
=13
