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Marizza181 [45]
3 years ago
13

Can someone please help me with this question?

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0
90% Because you he’s been getting 85 and higher
You might be interested in
2w+w^3-1/2w^2 for w=2
mars1129 [50]

The required value is 8

How can we find value?

We will find the value by putting the value of w in the given function to get the required value.

We can find the value of given function foe w=2 as shown below:

Given, function is 2w+w^3-1/2w^2

Let A=2w+w^3-1/2w^2

for w=2

A=2(2)+(2)^3-1/2(2)^2

= 2+8-1/2(4)

=2+8-2

=8

Hence, the required value is 8.

Learn more about function here:

brainly.com/question/875118

#SPJ1

8 0
1 year ago
A drawer contains 12 brown socks and 12 black socks, all unmatched. A man takes socks out at random in the dark. 21. Required in
avanturin [10]

Answer:

6  socks

Step-by-step explanation:

What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.

There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:

12/24

and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:

11/23

the final probability is the multiplication of these events:

(12/24) * (11/23)

P = 0.24

Now, to know how many you should get, we multiply the probability by the total number of socks, that is:

0.24 * 24 = 5.76

So you must take out at least 6 socks for the above to happen.

6 0
3 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
which of the following sets could be the sides of a right triangle? {2,3, square root 13} {5,5,2 square root 10} {5,12,15}
anastassius [24]

All of these sets meet the requirements of the triangle inequality. The sum of any two numbers in the set is greater than the third one. (You really only need to check that the sum of the smallest two is greater than the largest.)

It can help to resolve the numbers that are only indicated as to value.

√13 ≈ 3.606

2√10 ≈ 6.325

_____

Your comparisons can be ...

2 + 3 = 5 > 3.606 . . . is a triangle

5 + 5 = 10 > 6.325 . . . . . . is a triangle

5 + 12 = 17 > 15 . . . . . . . . is a triangle

8 0
3 years ago
QUICK PLEASE!! 100 POINTS!! PLEASE DONT GUESS!
allochka39001 [22]

Answer: B

Step-by-step explanation: I think

7 0
3 years ago
Read 2 more answers
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