Question

The length of a rectangle is 45 inches more than the width. The perimeter is 346 inches. Find the length and the width.

Answer 1

Answer:

Length = 109 inches and width = 64 inches

Step-by-step explanation:

Perimeter = 2(length + width)

Let the width of the rectangle be 'w' inches

Length of the rectangle would be = 45+w inches

2((45+w)+w) = 346

2(45+2w) = 346

90 + 4w = 346

4w = 346 - 90

4w = 256

w = $\frac{256}{4}$

w = 64 inches

Length = 45 + 64 = 109 inches

Length = 109 inches and width = 64 inches

Answer 2

Solution:

• Perimeter of Rectangle = 346

Let Required length of breadth be x

• Then, Length of Rectangle = 45 + x

Now, We have ;

• Perimeter of Rectangle = 2(l+b)
• Perimeter of Rectangle = 2 ( 45 + x + x
• 346 = 2 ( 45 + 2x )
• 346 = 90 + 4x
• 346 - 90 = 4x
• 256 = 4x
• x = 256 ÷ 4
• x = 64 inches

So, Length of Rectangle = x + 46

Length of Rectangle = 64 + 46

Length of Rectangle = 110 inches

Now, Breadth of Rectangle = 64 inches.