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Ratling [72]
3 years ago
14

You are traveling down the interstate averaging 50 mph. How much time has passed when you have traveled 120 miles

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0
To answer this all you have to do is divide the miles driven by how fast you are going. In this case 120/50=2.4 hours
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3 years ago
Match the equation with its corresponding solution for x.
Fudgin [204]

To solve for x, you need to isolate/get the variable "x" by itself in the equation:

3x - 3(x + 1) = 3     Distribute/multiply -3 into (x + 1)

3x + (-3)x + (-3)1 = 3

3x - 3x + 1 = 3

1 = 3

Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3

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2 years ago
The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
Not really getting this can someone plz explain.
Komok [63]

your answer would be b becuase that is 3/6 so thats half and ou would simply it and 1/4 do the same

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idk ......sorry‍♀️‍♀️‍♀️

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Read 2 more answers
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