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Naya [18.7K]
3 years ago
10

If someone covers 4 laps in 12 minutes what was the speed?

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0
If someone covers 4 laps in 12 minutes, he would be able to cover 1 lap in 3 minutes if that was the question. The question isn’t really clear.
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A garden measures 6 feet by 7 feet. A gravel path of constant width is placed around the garden so that the total area is 72 squ
frosja888 [35]
the answer is 114 because first u have to × and then +
4 0
3 years ago
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Write the ratio for sin P and cos Q
Gnom [1K]

Answer:

sin p -21/29

cos q 21/29 so here you go °~sohcahtoa~°

Step-by-step explanation:

sin means you find the soh part so you look for the oppisite over hyponuse

and for cos your looking for cah part so you find the adjsent over hypotnuse so the ansers is 21/29

4 0
3 years ago
Find the exact value
Mnenie [13.5K]

By using properties for <em>trigonometric</em> functions and <em>trigonometric</em> expressions, we find that the <em>exact</em> value of the sine of the angle 5π/12 radians is \frac{\sqrt{2+\sqrt{3}}}{2}.

<h3>How to find the exact value of a trigonometric expression</h3>

<em>Trigonometric</em> functions are <em>trascendent</em> functions, these are, that cannot be described algebraically. Herein we must utilize <em>trigonometric</em> formulae to calculate the <em>exact</em> value of a <em>trigonometric</em> function:

\sin \frac{5\pi}{12} = \sqrt{\frac{1 - \cos \frac{5\pi}{6} }{2} }

\sin \frac{5\pi}{12} = \sqrt{\frac{1 + \cos \frac{\pi}{6} }{2} }

\sin \frac{5\pi}{12} = \sqrt{\frac{1 + \frac{\sqrt{3}}{2} }{2} }

\sin \frac{5\pi}{12} =  \sqrt{\frac{2+\sqrt{3}}{4} }

\sin \frac{5\pi}{12} = \frac{\sqrt{2+\sqrt{3}}}{2}

By using properties for <em>trigonometric</em> functions and <em>trigonometric</em> expressions, we find that the <em>exact</em> value of the sine of the angle 5π/12 radians is \frac{\sqrt{2+\sqrt{3}}}{2}.

To learn more on trigonometric functions: brainly.com/question/15706158

#SPJ1

7 0
1 year ago
Kali is selling two different kinds of soup - tomato soup and clam chowder. She has a total of 80 bowls, so she can sell no more
algol13
You are looking for the shaded region that would be contained in both of the inequalities.

You have:
x+y \leq 805x+10y\ \textgreater \ 500

If you graph an shade the correct half-plane for those equations, you will see there is a triangular region on the left side of the first quadrant.
4 0
3 years ago
Can anyone help me?
Charra [1.4K]
                                                                    V = lwh
                                    2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
                 2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
                     2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
                                      (2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
                              (2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
                  (2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
                          (2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
                                    (2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
                                          (x + 4)(x + 2)           (x + 4)(x + 2)
                                                           2x + 5 = l
4 0
4 years ago
Read 2 more answers
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