Question

The nth term of a sequence is n^2 + 20.

Answer 1

Answer:

$\large\boxed{a)\ 21,\ 24,\ 29}\\\boxed{b)\ \text{five terms}}$

Step-by-step explanation:

$a_n=n^2+20\\\\a)\\\\\text{Substitute}\ n=1,\ n=2\ \text{and}\ n=3\ \text{to the }\ a_n:\\\\a_1=1^2+20=1+20=21\\\\a_2=2^2+20=4+20=24\\\\a_3=3^2+20=9+20=29$

$b)\\\\\text{You have to solve the inequality:}\\\\n^2+20$