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3 years ago

Help me please no coin thots I will report please explain your answer

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

8 0

the thing that sent me to da moon was that he said "COIN THOTS" hahsjfkovih5gjkcngjkefdhnguirwhfuihnfjifjkaskjcvxnukndrfuixk,cfikvmsdnwejrkoivbjrdfovibfdmerklovipfndem,jkflijfkdewrjldfvcbkfjewoivjdfewiopkdjvferowikfdjv im dead

Leokris [45]3 years ago

7 0

Should be equal to. sorry if its incorrect, but that's what i would go with.

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Equation for the given function

Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 ) this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2 and c=1

2) the x- intercept is : 4

so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

means x-4=0 ... ( x+2 ≠ 0)

note :

g(x) ≠ (x-4)/(x-1) except in the case x ≠ -2

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3 years ago

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Answer: x < 11.9

Step-by-step explanation:

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3 years ago

What is the first step in the constitution of a line perpendicular to AB and passing through an external point M?

NikAS [45]

take your compass on a point on your line. then draw a circle. take the 2 points in which the circle hit the line and draw 2 circles larger than half the distance between he 2 points. take the point that they intersect and and connect it to the line and you point M and it is purpendicular. does that make sense?

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3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago