Answer:
<em>The correct answer is: False</em>
Step-by-step explanation:
<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.
Here, 
but, 
So, a circle can't be circumscribed about the given quadrilateral.
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

First you add 3/4 and 2/3 you but then do 3/4 2/3 you think what the both can go to is 12 the dominator is 12 then you time it by 3,4 because they both go to 12 then the 3 will be time 3 because 4 x 3 = 12 then you do it the top so 3x3 = 9 9/12 then you do the next one is2/3 do the same then will get 8/12 then you can subtract it 9/12 - 8/12 will gave you 1/12
(0.00142857)=-x is your answer