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cricket20 [7]
4 years ago
12

There are 15 cherry, 17 grape, and 14 orange juice boxes in the cooler. What is the probability of randomly selecting a cherry t

hen selecting a grape without replacement?
Question 3 options:

17/138


119/1058


136/1035


29/46
Mathematics
2 answers:
Nutka1998 [239]4 years ago
4 0
15 +17 +14 = 46 juice boxes total

15 cherry = 15/46

17 grape = 17/45

15/46 * 17/45 = 17/138
Art [367]4 years ago
3 0
15 cherry, 17 grape, and 14 orange....total of 46 juice boxes

P(cherry) = 15/46
without replacing
P(grape) = 17/45 (I put it over 45 because since the 1st was not replaced, we have 1 less juice box)

P (both events happening) = 15/46 * 17/45 = 17/138 <==

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4x+3y=32 <br> 4x+y=16<br><br> work out x and y pleaseeeeeee
Marrrta [24]

Answer:

The answer is xy=16-4 and xy=12

3 0
2 years ago
30% of the people at a concert are female. 1295 of the people at the concert are male. Work out the number of people at the conc
liubo4ka [24]
Total number of people = n
Number of female = 30/100 n
Number of male = 1295

Number of females = 579 total female
6 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.

8 0
3 years ago
Please I need the answer ASAP I have 28 points
natka813 [3]
2/7 x 1/3 = 2/21. it is already simplified so your answer is 2/21
7 0
3 years ago
shenika is inviting 7 friends to a party. if each friend will get 5 cookies and each box has 12 cookies. how many boxes does she
Naddik [55]

Answer:

Shenika invites 7 friends and each one gets 5 cookies.

= 7*5

= 35

Based on above answer, Shenika will need a total of 35 cookies for all.

-----------------------------------------------------------------------------------------------------------

Each box has 12 cookies.

Total cookies = 35

Let the number of boxes be x.

12*x = 35

x = 35/12

x = 2.9

This means she would need <em><u>3 boxes</u></em>.

8 0
3 years ago
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