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3 years ago

10

36 POINTS! Write a problem where the negative square root is not an integer. then graph the square root(tell me what to graph si

nce we cant on here)

1 answer:

Tcecarenko [31]3 years ago

7 0

<span>" - √5 "....and 'square root ' is statement and difficult to graph....you need a function</span>

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Nathan has a sculpture in the shape of a pyramid. The height of the sculpture is 3 centimeters less than the side length, x, of

uysha [10]

Let
x-----------> <span>the side length of a pyramid square base
h-----------> t</span>he height of the sculpture <span>in the shape of a pyramid

we know that
h=(x-3)
Volume=162 cm</span>³
Volume=x² *(x-3)/3
then
x² *(x-3)/3=162----------> x³-3x²=486----------> x³-3x²-486=0
x³-3x²-486=0-------- <span>this equation can be used to find the length of the sculpture’s base

using a graph tool-----------> </span>to find the solution
x=9 cm -------------> see the attached figure
h=(x-3)-----> h=9-3--------> h=6 cm

the answer is
<span>the length of the sculpture’s base is 9 cm
</span>the height of the sculpture is 6 cm

8 0

3 years ago

Heidi is driving 200 miles. She has finished 80% of the drive. How many miles is 80% of Heidi's drive.

algol [13]

Answer:

160 miles

Step-by-step explanation:

200 * 0.8 is 160

3 0

3 years ago

Read 2 more answers

If a figure located at T(-3, -1), U(1, -2), V(2, 2), W(-1, 1) and is rotated 90∘ counterclockwise rotation about the origin, whi

damaskus [11]

Answer:

(1, - 3 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ), thus

T(- 3, - 1 ) → T'(1, - 3 )

3 0

3 years ago

Express sin A, cos A, and tan A as ratios

vlabodo [156]

<h3>Answer: Choice B</h3><h3>sqrt(3)/2, 1/2, sqrt(3)</h3>

================================================

Explanation:

Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12

Sin(angle) = opposite/hypotenuse

sin(A) = BC/AB

sin(A) = 6sqrt(3)/12

sin(A) = sqrt(3)/2

---------------

Cosine is the ratio of the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(A) = AC/AB

cos(A) = 6/12

cos(A) = 1/2

---------------

Tangent is the ratio of the opposite and adjacent

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 6sqrt(3)/6

tan(A) = sqrt(3)

5 0

3 years ago

Which of the following equations is represented by a graph that is centered at (- 6, - 8) and includes the point (0, - 8) ?

Lera25 [3.4K]

Answer:

C.

Step-by-step explanation:

As the center is (-6, -8) the 2 factors on the left will be (x + 6) and (x + 8) so it's either A or C.

When x = 0 y = -8 so substituting we have:

(0 + 6)^2 + (-8 + 8)^2 = 36 + 0 = 36.

So it's choice C.

4 0

3 years ago