Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:
Option C: 38 is p more than 25
Step-by-step explanation:
the equation 25 + p = 38
can be read as 38 is 25 plus p units, or similarly ;
38 is p units more than 25.
Therefore from the three sentences you are showing, only the last one (option C) is the correct one.
Your answer will be X=4c−b<span>
I hope helped ^-^
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X + 2y = 10 becomes x + 2(2x-4) = 10. Thus, x + 4x - 8 = 10, and 5x = 18.
