Which of the following equations have no real solution but have two complex solutions?

Mathematics

1 answer:

Helga [31]3 years ago

5 0

Answer: 3x^2 - 5x = -8, 2x^2 = 6x - 5 and -x^2 -10x = 34

Explanation:

Because there discriminant are less than 0

Discriminant = b^2 - 4ac

We use this formula to determine the if the equation has real roots or not

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Which statement about the ordered pairs (-9, 3) and (2, - 4) is true for the equation 6.0 6x - 142 2 9. 3) is a solution to the

CaHeK987 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)

andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

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3 years ago

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Effectus [21]

The equation of the rotating light is an illustration of a secant function

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