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pogonyaev
3 years ago
6

Which of the following equations have no real solution but have two complex solutions?

Mathematics
1 answer:
Helga [31]3 years ago
5 0
Answer: 3x^2 - 5x = -8, 2x^2 = 6x - 5 and -x^2 -10x = 34

Explanation:

Because there discriminant are less than 0

Discriminant = b^2 - 4ac

We use this formula to determine the if the equation has real roots or not
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y=−x+573, x+y=573

Step-by-step explanation:

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Any people with a crack head personality up for a c.hat? O-o
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hi

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Find the measure of ∠C.
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Answer:

C = 20

Step-by-step explanation:

The sum of the angles of a triangle is 180

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Given the function g(x) = 41x3 + a for some constant a, which describes the inverse function
Paha777 [63]

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When we have a function g(x) such that:

g(x) = y.

Then the inverse, h(x), must be such that:

h(y) = x.

This means that:

g( h(x) ) = x

h( g(x) ) = x.

In this case, g(x) = 41*x^3 + a.

Then:

g( h(x)) = x = 41*h(x)^3 + a.

Now we can solve it for h(x).

             x - a = 41*h(x)^3

             (x - a)/41 = h(x)^3

            ∛( (x -a)/41 ) = h(x)

h(x) is the inverse function of g(x).

7 0
3 years ago
A tunnel is constructed with a semielliptical arch. The width of the tunnel is 60 feet, and the maximum height at the center of
rusak2 [61]

The height of the tunnel 5 feet from the edge is 13.82 feet option second 13.82 feet is correct.

<h3>What is an ellipse?</h3>

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have:

A tunnel is constructed with a semi-elliptical arch. The width of the tunnel is 60 feet, and the maximum height at the center of the tunnel is 25 feet.

2a = 60 (width of the tunnel is 60 feet)

a = 30

And the maximum height at the center of the tunnel is 25 feet

b = 25

Let's assume the center of the ellipse is at the origin.

So the equation of the ellipse:

\rm \dfrac{x^2}{30^2}+\dfrac{y^2}{25^2}=1

Now plug x = a - 5 = 30 - 5 = 25

\rm \dfrac{25^2}{30^2}+\dfrac{y^2}{25^2}=1

After solving:

\rm \dfrac{y^2}{25^2}=1-\dfrac{25}{36}

\rm y^2=\dfrac{6875}{36}

y = ±13.819 ≈ ±13.82

Height cannot be negative

y = 13.82 feet

Thus, the height of the tunnel 5 feet from the edge is 13.82 feet option second 13.82 feet is correct.

Learn more about the ellipse here:

brainly.com/question/19507943

#SPJ1

5 0
1 year ago
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