1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
11111nata11111 [884]
3 years ago
15

Michelle wants to make cupcakes for her daughter's birthday. The recipe calls for 3/4 cup of brown sugar, 1 1/2 cups of white su

gar and 2 cups of powdered sugar and will make 12 cupcakes. how much sugar will be in each cupcake?
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
Well you want to add 3/4 , 1 1/2, and 2. Then divide that answer by 12.


You might be interested in
Ples help me find slant assemtotes
FrozenT [24]
A polynomial asymptote is a function p(x) such that

\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0

(y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form p(x)=ax+b.

Ignore the negative root (we don't need it). If y=2x-1+2\sqrt{x^2-x}, then we want to find constants a,b such that

\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

We have

\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}
\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}
\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}

since x\to\infty forces us to have x>0. And as x\to\infty, the \dfrac1x term is "negligible", so really \sqrt{x^2-x}\approx x. We can then treat the limand like

2x-1+2x-ax-b=(4-a)x-(b+1)

which tells us that we would choose a=4. You might be tempted to think b=-1, but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of b, we have to solve for it in the following limit.

\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0

\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2

We write

(\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}

Now as x\to\infty, we see this expression approaching -\dfrac12, so that

-\dfrac12=\dfrac{b+1}2\implies b=-2

So one asymptote of the hyperbola is the line y=4x-2.

The other asymptote is obtained similarly by examining the limit as x\to-\infty.

\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0

Reduce the "negligible" term to get

\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0

Now we take a=0, and again we're careful to not pick b=-1.

\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0

\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2

(x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac
 x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}

This time the limit is \dfrac12, so

\dfrac12=\dfrac{b+1}2\implies b=0

which means the other asymptote is the line y=0.
4 0
3 years ago
A sign company charges $28 per yard for each custom made banner. Ms. Gill orders two banners that are each 1 7/8 yards yards lon
Svetlanka [38]

Answer:

$896

Step-by-step explanation:

We are given that

Charge of 1 yard for each custom-made banner=$28

Length of 1 piece=15 yards

Length of another piece=2 yards

We have to find that how much money payed by Ms.Gill for all three banners.

According to question

Cost of 15 yards long banner=$420

Cost of 2 piece of 15 yards long banner==$840

Cost of 2 yards long banner==$56

Total cost of 3 piece of banners=840+56=$896

Hence, Ms gill pay for all three banners=$896

Your Welcome;)

8 0
3 years ago
What is the strongest relationship you can infer between two variables from this statement?
Dmitry [639]

Answer:

hope this helps you with your question

3 0
3 years ago
A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0
3 years ago
1.Find by factors the square root of 3600<br>2. Find by factors the cube root of 343​
Contact [7]

Answer:

1)60

2)7

Step-by-step explanation:

1)The square root of 3600 is 60. It is the positive solution of the equation x2 = 3600. The number 3600 is a perfect square.

2)The cube root of 343 is the number which when multiplied by itself three times gives the product as 343. Since 343 can be expressed as 7 × 7 × 7. Therefore, the cube root of 343 = ∛(7 × 7 × 7) = 7.

4 0
2 years ago
Read 2 more answers
Other questions:
  • What is the grates common factor of 16 and 48
    12·2 answers
  • How do you graph a circle x^2 + y^2=25 and the line is given y=2
    15·1 answer
  • What is the area of a triangle whose vertices are G(−1, 2), H(5, 2) and K(8, −3)
    15·1 answer
  • The following equation was correctly simplified:
    5·1 answer
  • Write the following ratio using two other notations.<br> 3 to 2
    9·1 answer
  • HELP!!!!! Help plz thx
    15·1 answer
  • Neeeeeeed helpppppppppppppp
    14·2 answers
  • No links or silly answers or blank answers you will be reported
    7·2 answers
  • If both pairs of opposite sides of a quadrilateral are congruent, then thequadrilateral is a parallelogram.A. TrueB. False
    12·1 answer
  • Probability of rolling a 6 with two dice one with values 1, 2, 2, 3, 3, 4 and 1, 3, 4, 5, 6, 8
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!