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4 years ago

Which one of the two potential differences emf or terminal voltage will be greater in magnitude?Why?

Physics

1 answer:

tresset_1 [31]4 years ago

8 0

Answer:

True, yes terminal voltage of a battery can never be greater than the emf of the battery. Because due to internal resistance of the current terminal

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Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters above the surface.

Serhud [2]

Answer:

Correct answer: E total = 2,800 J

Explanation:

Given:

m = 4 kg the mass of the object

V = 20 m/s the speed (velocity) of the object

H = 50 m the height of the object above the surface

E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

Ep = m g H we take g = 10 m/s²

Ep = 4 · 10 · 50 = 2,000 J

Ek = m V² / 2

Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

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3 years ago

A laser used to dazzle the audience at a rock concert emits blue light with a wavelength of 463 nm . calculate the frequency of

ZanzabumX [31]

The wavelength of light is given as 463 nm or can also be written as 463 x 10^-9 m. [wavelength = ʎ]

We know that the speed of light is 299 792 458 m / s or approximately 3 x 10^8 m / s. [speed of light = c]

Given the two values, we can calculate for the frequence (f) using the formula:

f = c / ʎ

Substituting the given values:

f = (3 x 10^8 m / s) / 463 x 10^-9 m

f = 6.48 x 10^14 / s = 6.48 x 10^14 s^-1

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3 years ago

Which phrase provides the best context clue for the meaning of the word tabulate?

Paul [167]

Answer:

round and count

Explanation:

means arrange, order, organize, etc

6 0

3 years ago

Read 2 more answers

A tiger leaps horizontally from a high rock with a speed of 4.5 m/s. She lands 50 m away

VladimirAG [237]

A tigers lost one and yyyyyyyy was the first day in a while and they didn’t have a back up 4.5 50m

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3 years ago

An automobile with a tangential speed of 54.1 km/h follows a circular road that has a radius of 41.6 m. The automobile has a mas

Viefleur [7K]

1) Available force of friction: 6174 N

2) No

Explanation:

The magnitude of the frictional force between the car's tires and the pavement of the road is given by

$F_f=\mu mg$

where

$\mu$ is the coefficient of friction

m is the mass of the car

g is the acceleration of gravity

For the car in this problem, we have:

$\mu=0.500$ (coefficient of friction)

m = 1260 kg (mass of the car)

$g=9.8 m/s^2$

Therefore, the force of friction is

$F_f=(0.500)(1260)(9.8)=6174 N$

In order to mantain the car in circular motion, the force of friction must be at least equal to the centripetal force.

The centripetal force is given by

$F=m\frac{v^2}{r}$

where

m is the mass of the car

v is the tangential speed

r is the radius of the curve

In this problem, we have

m = 1260 kg

$v=54.1 km/h =15.0 m/s$ is the tangential speed

r = 41.6 m is the radius of the curve

Therefore, the centripetal force is

$F=(1260)\frac{15.0^2}{41.6}=6814 N$

Therefore, the force of friction is not enough to keep the car in the curve, since $F_f$

4 0

4 years ago

Which one of the two potential differences emf or terminal voltage will be greater in magnitude?Why?​

Which one of the two potential differences emf or terminal voltage will be greater in magnitude?Why?