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JulijaS [17]
3 years ago
10

NEED BOTH QUESTIONED ANSWERED ASAP.

Physics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

the answer is the red super giants

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A charged capacitor is connected to an ideal inductor to form an LC circuit with a frequency of oscillation f = 1.6 Hz. At time
IrinaK [193]

Answer:

8.0\mu C

Explanation:

We are given that

f=1.6 Hz

q=3.0\mu C=3.0\times 10^{-6} C

1\mu C=10^{-6} C

Current,I=75\mu A=75\times 10^{-6} A

1\mu A=10^{-6} A

We have to find the maximum charge of the capacitor.

Charge on the capacitor,q=q_0cos\omega t

\omega=2\pi f=2\pi\times 1.6=3.2\pi rad/s

3\times 10^{-6}=q_0cos3.2\pi t....(1)

I=\frac{dq}{dt}=-q_0\omega sin\omega t

75\times 10^{-6}=-q_0(3.2\pi)sin3.2\pi t....(2)

Equation (2) divided by equation (1)

-3.2\pi tan3.2\pi t=\frac{75\times 10^{-6}}{3\times 10^{-6}}=25

tan3.2\pi t=-\frac{25}{3.2\pi}=-2.488

3.2\pi t=tan^{-1}(-2.488)=-1.188rad

q_0=\frac{q}{cos\omega t}=\frac{3\times 10^{-6}}{cos(-1.188)}=8.0\times 10^{-6}=8\mu C

Hence, the maximum charge of the capacitor=8.0\mu C

4 0
4 years ago
A force of 100N is applied to an area of 100mm².what is the pressure exerted on the area in N/m².​
Dmitry_Shevchenko [17]

Answer:

P = 1000000[Pa] = 1000 [kPa]

Explanation:

To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.

P=F/A

where:

P = pressure [Pa] (units of pascals)

F = force = 100 [N]

A = area = 100 [mm²]

But first we must convert the units from square millimeters to square meters.

A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2}  } =0.0001[m^{2} ]

Now replacing:

P=100/0.0001\\P=1000000[Pa]

3 0
3 years ago
If I Throw a bowling ball and a tennis ball from a building, describe if one would hit the ground first and why.
olga nikolaevna [1]

Answer:

The bowling ball would

Explanation:

Because it contains more weight! And that will make it fall down quicker.

Hope it helped

3 0
3 years ago
Which is not an example of how an object gains elastic potential energy by stretching?
lora16 [44]
C because you don’t put a force of which you choose and the force wouldn’t be strong enough
4 0
4 years ago
A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force
lozanna [386]

The total force on the ground due to the bricks is 47,040 N.

<h3>Total force on the ground</h3>

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

  • Fₙ is normal force
  • m is mass of the brickes
  • g is acceleration due to gravity

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

Learn more about total force here: brainly.com/question/14361879

#SPJ1

5 0
2 years ago
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