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4 years ago

Fill in the blanks

Physics

2 answers:

Inessa05 [86]4 years ago

5 0

Answer:

1. <u>Gravity</u>

2. <u>Matter</u>

Explanation:

According to Giant impact theory, when a Mars sized object collide with the Earth, the debris was held close to Earth due to its gravity. The debris collided frequently forming a planetesimal which grew in size overtime. Thereby, the gravity increased and pulled even more matter. The accretion of this matter eventually formed the Moon.

Nataly_w [17]4 years ago

4 0

Answer:

Word for the first blank: gravity

Word for the second blank: matter

Explanation:

The only way debris from the impact with Earth can be held close to Earth is due to a force. The only force that could be acting from Earth is "the force of gravity".

The gravitational pull of this new object being formed, increases proportional to its mass as more and more "matter" accumulates. And the accretion process is now on its way.

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Suppose a star the size of our Sun, but with mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 7.0 days.

kvasek [131]

Answer:

Its rotation will be 3.89x10⁴ rad/s.

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We can find the rotation speed by conservation of the angular momentum:

$L_{i} = L_{f}$

$I_{i}\omega_{i} = I_{f}\omega_{f}$ (1)

The initial angular speed is:

$\omega_{i} = \frac{1 rev}{7 d} = 0.14 \frac{rev}{d}$

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$I = \frac{2}{5}mr^{2}$ (2)

Where m is 9 times the sun's mass and r is the sun's radius

By entering equation (2) into (1) we have:

$\frac{2}{5}m_{i}r_{i}^{2}\omega_{i} = \frac{2}{5}m_{f}r_{f}^{2}\omega_{f}$

$9m_{sun}(696342 km)^{2}0.14\frac{rev}{d} = \frac{3}{4}9m_{sun}(13 km)^{2}\omega_{f}$

$\omega_{f} = \frac{4}{3}*0.14 \frac{rev}{d}(\frac{696342 km}{13 km})^{2} = 5.36 \cdot 10^{8} \frac{rev}{d}*\frac{1 d}{24 h}*\frac{1 h}{3600 s}*\frac{2\pi rad}{1 rev} = 3.89 \cdot 10^{4} rad/s$

Hence, its rotation will be 3.89x10⁴ rad/s.

I hope it helps you!

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4 years ago

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