Given:
P = 1000 W, power input
c = 4190 J/(kg-K), the specific heat of water
m = 1 kg, mass of water
ΔT = 10 °C = 10 K, temperature rise.
Let t = time required to raise the temperature f the water.
Then
P*t = m*c*ΔT
(1000 J/s)*(t s) = (1 kg)*(4190 J/(kg-K)*(10 K)
1000t = 41900
t = 41.9 s
Answer: 41.9 s or 42 s (approximately)
Acceleration = force/mass
1/4
s=ut+1/2at^2
0*4+1/2*1/4*4^2
1/2*1/4*16
1/2*4
=2
Answer:
The average acceleration is 
Explanation:
<u>Uniform Acceleration
</u>
When an object varies its velocity at the same rate, the acceleration is constant.
The relation between the initial and final speeds is:

Where:
vf = Final speed
vo = Initial speed
a = Constant acceleration
t = Elapsed time
The acceleration can be calculated by solving for a:

The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:

The average acceleration is 
Answer:
a. FALSE
b.TRUE
C. FALSE
Explanation:
The formula fot the distance between two points is given as

hence we determine the distances between all the points
a.P(3,2,-4), Q(1,0,-4), R(2,1,1)

For point PR
we have


B. For point RP

for point RQ we have

|RP|=|R Q|
C.

For point Q R

