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3 years ago

7

What happens if 5 Protons combine with 4 neutrons.

2 answers:

lianna [129]3 years ago

7 0

in the case of beryllium, a light metal, only the beryllium-9 isotope is stable with its 9 nucleons (i.e. 4 protons and 5 neutrons)

Hope this helps so sorry if it does not help

JulijaS [17]3 years ago

6 0

They go looking for 5 electrons to join them and make one whole atom of Boron.

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The specific heat of water is 4190 j/(kg*k). suppose you put 1 kg of water (a bit over 4 cups) into a microwave that can deliver

VladimirAG [237]

Given:
P = 1000 W, power input
c = 4190 J/(kg-K), the specific heat of water
m = 1 kg, mass of water
ΔT = 10 °C = 10 K, temperature rise.

Let t = time required to raise the temperature f the water.
Then
P*t = m*c*ΔT
(1000 J/s)*(t s) = (1 kg)*(4190 J/(kg-K)*(10 K)
1000t = 41900
t = 41.9 s

Answer: 41.9 s or 42 s (approximately)

4 0

3 years ago

18. A net force of 1.0N acts on a 4.0-kg object, initially at rest, for 4.0 seconds. What is the distance the object moves durin

hjlf

Acceleration = force/mass
1/4
s=ut+1/2at^2
0*4+1/2*1/4*4^2
1/2*1/4*16
1/2*4
=2

6 0

4 years ago

Read 2 more answers

An Indy 500 race car's velocity increases from 4.0 m/s to +36

Soloha48 [4]

Answer:

The average acceleration is $8\ m/s^2$

Explanation:

<u>Uniform Acceleration </u>

When an object varies its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

$v_f=v_o+a.t$

Where:

vf = Final speed

vo = Initial speed

a = Constant acceleration

t = Elapsed time

The acceleration can be calculated by solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:

$\displaystyle a=\frac{36-4}{4}=8\ m/s^2$

The average acceleration is $8\ m/s^2$

3 0

3 years ago

A triangle ∆P QR has vertices P(3, 2, −4), Q(1, 0, −4), R(2, 1, 1). Use the distance formula to decide which one of the followin

777dan777 [17]

Answer:

a. FALSE

b.TRUE

C. FALSE

Explanation:

The formula fot the distance between two points is given as

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} +(z_{2}-z_{1})^{2}}\\$

hence we determine the distances between all the points

a.P(3,2,-4), Q(1,0,-4), R(2,1,1)

$PQ=\sqrt{(1-3)^{2} +(0-2)^{2} +(-4-(-4))^{2}}\\PQ=\sqrt{4+4+0}\\ PQ=\sqrt{8}$

For point PR

we have

$PR=\sqrt{(2-3)^{2} +(1-2)^{2} +(1-(-4))^{2}}\\PR=\sqrt{1+1+9}\\ PR=\sqrt{11}\\$

$|PQ|\neq |PR|$

B. For point RP

$RP=\sqrt{(3-2)^{2} +(2-1)^{2} +(-4-1)^{2}}\\RP=\sqrt{1+1+25}\\ RP=\sqrt{27}$

for point RQ we have

$RQ=\sqrt{(1-2)^{2} +(0-1)^{2} +(-4-1)^{2}}\\RQ=\sqrt{1+1+25}\\ RQ=\sqrt{27}$

|RP|=|R Q|

C.

$QP=\sqrt{(3-1)^{2} +(2-0)^{2} +(-4+4)^{2}}\\QP=\sqrt{4+4+0}\\ QP=\sqrt{8}$

For point Q R

$QR=\sqrt{(2-1)^{2} +(1-0)^{2} +(1-(-4))^{2}}\\QR=\sqrt{1+1+9}\\ QR=\sqrt{11}\\$

$QP\neq QR$

6 0

3 years ago

Scientist have been able to determine the composition of Earth's layers by:

Pie

D is the correct answer

4 0

3 years ago