Answer:
Explanation:
We can solve this problem using the principle of conservation of energy.
Starting point. For higher up the ramp
Em₀ = U = m g h
where h is the height of the ramp h = 3.00 m
Final point. For low
Em_{f} = K = ½ m v²
as there is no friction the mechanical energy is conserved
Em₀ =
m g h = ½ m v²
v = √ (2g h)
let's calculate
v = √(2 9.8 3.00)
v = 7.668 m / s
Answer:
0.04225 Nm
Explanation:
N = Force applied = 5 N
= Coefficient of static friction = 0.65
d = Diameter of knob = 1.3 cm
r = Radius of knob =
Force is given by
When we multiply force and radius we get torque
Torque on thumb
Torque on forefinger
The total torque is given by
The most torque that exerted on the knob is 0.04225 Nm
Answer:
37.7 J
Hope this helps! (see pictures)
