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quester [9]
2 years ago
13

Imagine que su primo Morton baja en patineta por una rampa curva en un parque. Tratando a Morton y su patineta como una partícul

a, esta describe un cuarto de circulo de Radio= 3.00 m (ver figura) La masa total de Morton y su patineta es de 33 Kg. El parte del reposo y no hay fricción. Calcule su rapidez en la base de la rampa.
Physics
1 answer:
nevsk [136]2 years ago
7 0

Answer:

Explanation:

We can solve this problem using the principle of conservation of energy.

Starting point. For higher up the ramp

          Em₀ = U = m g h

where h is the height of the ramp h = 3.00 m

Final point. For low

          Em_{f} = K = ½ m v²

as there is no friction the mechanical energy is conserved

          Em₀ = Em_{f}

          m g h = ½ m v²

          v = √ (2g h)

let's calculate

         v = √(2 9.8 3.00)

         v = 7.668 m / s

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Why does the entropy of a gas increase when it expands into a vacuum? Why does the entropy of a gas increase when it expands int
Mrrafil [7]

Answer:

The entropy of a gas increases when it expands into a vacuum because the number of possible states increases .

Explanation:

When a gas expand in a vacuum, the molecules of the gases vibrates very fast and starting moving with higher velocity in random directions which means the level of disorder in the gases increases.

Now the possible state of the gas molecule increases such as the particle can be located at different position due to increased randomness.

<u>Entropy is the measure of this randomness and thus with this increased randomness entropy also increases.</u>

6 0
3 years ago
An electric field from a charge has a magnitude of 1.5 × 104 N/C at a certain location that points inward. If another charge wit
zysi [14]

Answer:

-0.045 N, they will attract each other

Explanation:

The strength of the electrostatic force exerted on a charge is given by

F=qE

where

q is the magnitude of the charge

E is the electric field magnitude

In this problem,

q=3.0\cdot 10^{-6}C

E=-1.5\cdot 10^4 N/C (negative because inward)

So the strength of the electrostatic force is

F=(-3.0\cdot 10^{-6}C)(1.5\cdot 10^4 N/C)=-0.045 N

Moreover, the charge will be attracted towards the source of the electric field. In fact, the text says that the electric field points inward: this means that the source charge is negative, so the other charge (which is positive) is attracted towards it.

6 0
3 years ago
Read 2 more answers
A proton in a high-energy accelerator is given a kinetic energy of 50.0 GeV. Determine (a) the momentum and (b) the speed of the
koban [17]

(a) The momentum of the proton is determined as 5.17 x 10⁻¹⁸ kgm/s.

(b) The speed of the proton is determined as  3.1 x 10⁹ m/s.

<h3>Momentum of the proton</h3>

The momentum of the proton is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg
  • v is speed of the proton = ?
<h3>Speed of the proton</h3>

v² = 2K.E/m

v² = (2 x 50 x 10⁹ x 1.602 x 10⁻¹⁹ J)/(1.67 x 10⁻²⁷)

v² = 9.6 x 10¹⁸

v = 3.1 x 10⁹ m/s

<h3>Momentum of the proton</h3>

P = mv = (1.67 x10⁻²⁷ x 3.1 x 10⁹) = 5.17 x 10⁻¹⁸ kgm/s

Learn more about momentum here: brainly.com/question/7538238

#SPJ4

4 0
1 year ago
A projectile is launched with an initial velocity of 25m/s at 35 degrees above the horizontal. assuming that the projectile retu
Dovator [93]
Speed is the same as the initial: 25m/s.

*if* you need vectors though:

final velocity = (25*cos(35), -25*sin(35) ) m/s


3 0
3 years ago
With what velocity Must a 0.53 kg softball be moving to be equal to the momentum of a 0.31 kg baseball moving at 21 m/s
vladimir2022 [97]

Answer:12.28m/s

Explanation:

momentum of baseball =mass of baseball x velocity of baseball

Momentum of baseball =0.31x21

Momentum of baseball =6.51kgm/s

For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball

6.51=0.53 x velocity of softball

Velocity of softball =6.51/0.53

Velocity of softball =12.28m/s

3 0
3 years ago
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