Answer:
Explanation:
We can solve this problem using the principle of conservation of energy.
Starting point. For higher up the ramp
Em₀ = U = m g h
where h is the height of the ramp h = 3.00 m
Final point. For low
Em_{f} = K = ½ m v²
as there is no friction the mechanical energy is conserved
Em₀ =
m g h = ½ m v²
v = √ (2g h)
let's calculate
v = √(2 9.8 3.00)
v = 7.668 m / s
Answer:
The value of the distance is .
Explanation:
The velocity of a particle(v) executing SHM is
where, is the angular frequency,
is the amplitude of the oscillation and
is the displacement of the particle at any instant of time.
The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., .
The maximum velocity() is
Divide equation (1) by equation(2).
Given, and
. Substitute these values in equation (3).
Answer:
Induced emf in the coil, E = 0.157 volts
Explanation:
It is given that,
Number of turns, N = 100
Diameter of the coil, d = 3 cm = 0.03 m
Radius of the coil, r = 0.015 m
A uniform magnetic field increases from 0.5 T to 2.5 T in 0.9 s.
Due to this change in magnetic field, an emf is induced in the coil which is given by :
E = -0.157 volts
Minus sign shows the direction of induced emf in the coil. Hence, the induced emf in the coil is 0.157 volts.