The 3 cm vector represents 63 km.
Since a 1 cm long vector represents a displacement of 21 km, we need to find the number of kilometers a 3 cm vector represents.
Let x represent the displacement the 3 cm vector represents.
By ratio, we have 1 cm: 21 km = 3 cm : x
So, 1 cm/21 km = 3 cm/x
Cross-multiplying, we have
x × 1 cm = 3 cm × 21 km
x = 3 cm × 21 km/1 cm
x = 63 km
So, the 3 cm vector represents a displacement of 63 km.
Learn more about displacement here:
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Answer:
15000N/m²
Explanation:
Given parameters:
Weight = 450N
Total area = 0.03m²
Unknown:
Pressure under her feet = ?
Solution:
Pressure is the force per unit area on a body.
Pressure =
Weight is a type of force;
Pressure =
= 15000N/m²
Answer:
Explanation:
Let the time required for acceleration a₁ and deceleration a₂ be t₁ and t₂ .
Since final velocity during acceleration and initial velocity during deceleration are same
a₁ t₁ = a₂ t₂
5t₁ = 2 t₂ ------------------------------------------ ( 1 )
Distance travelled during acceleration = 1/2 a₁t₁²
= 1/2 x 5 x t₁² = 2.5 t₁²
Distance travelled during deceleration = 1/2 a₂t₂²
= 1/2 x 2 x t₂² = t₂²
Total distance travelled = 2 miles = 2 x 1760 x 3 ft = 10560
2.5 t₁² + t₂² = 10560
2.5 ( 2t₂ / 5 )² + t₂² = 10560
.4 t₂² + t₂² = 10560
1.4 t₂² = 10560
t₂ = 86.85 s
t₁ = 2t₂ / 5 = 34.75 s
t₁ + t₂ = 121.6 = 122 s
Total time taken = 122 s .
maximum velocity = a₁t₁
= 5 x 34.75 = 173.75 = 174 m/s .